从DataSet生成JSON

时间:2013-12-18 06:08:15

标签: c# json extjs4

我正在使用ExtJS生成一棵树。它需要以下格式的JSON:

{  "children": [{
        "text": "Invisible",
        "expanded": true,
        "children": [{
            "text": "Billing",
            "leaf": true
        }, {
            "text": "Sales",
            "leaf": true
        }]
    },
    {
        "text": "Visible",
        "expanded": true,
        "children": [{
            "text": "Equipment",
            "leaf": true
        }, {
            "text": "Process",
            "leaf": true
        }]
    }]
}

我在DataSet中的结果是:

文本可见叶展开
帐单0真的假
销售0真的假
设备1真假
过程1个真假

所有带有visible ='1'的记录应该在'Visible'节点下生成,所有带有visible ='0'的记录应该在'Invisible'节点下生成。我只是无法生成JSON。如何以上述格式生成它?

1 个答案:

答案 0 :(得分:0)

我创建了一个类,如下所示:

public class TreeNode
{
    public string text { get; set; }
    public bool leaf { get; set; }
    public bool expanded { get; set; }
    public List<TreeNode> children { get; set; }

    public TreeNode()
    {
        leaf = false;
        expanded = true;
        children = new List<TreeNode>();
    }
}

根据返回的数据集,我按如下方式创建了对象:

List<TreeNode> treeNodeList = new List<TreeNode>();
            treeNodeList.Add(new TreeNode
            {
                text = "Invisible",
                expanded = true,
                leaf = false
            });
            treeNodeList.Add(new TreeNode
            {
                text = "Visible",
                expanded = true,
                leaf = false
            });

            if (ds.Tables.Count > 0)
            {
                for (int i = 0; i < ds.Tables[0].Rows.Count; i++)
                {
                    treeNodeList[0].children.Add(new TreeNode
                                        {
                                            text = ds.Tables[0].Rows[i][0].ToString(),
                                            leaf = true
                                        });
                }
            }

            if (ds.Tables.Count > 1)
            {
                for (int i = 0; i < ds.Tables[1].Rows.Count; i++)
                {
                    treeNodeList[1].children.Add(new TreeNode
                    {
                        text = ds.Tables[1].Rows[i][0].ToString(),
                        leaf = true
                    });
                }
            }
            return treeNodeList;