Oracle SQL count（）每小时

Question

我有一个查询，显示每个运营商每小时的发货量。我按小时计算它，但是在上一小时完成之前它显示为零，然后报告下一小时的数据。基本上，想要从左到右阅读，如果运营商在那个小时内没有发货，则为NULL。

代码：

    select router_destination_code, 
count(case when to_char(app_last_updated_date_utc, 'HH24') = '00' then router_destination_code else NULL end) as "Hour 1",
count(case when to_char(app_last_updated_date_utc, 'HH24') = '01' then router_destination_code else NULL end) as "Hour 2",
count(case when to_char(app_last_updated_date_utc, 'HH24') = '02' then router_destination_code else NULL end) as "Hour 3",
count(case when to_char(app_last_updated_date_utc, 'HH24') = '03' then router_destination_code else NULL end) as "Hour 4",
count(case when to_char(app_last_updated_date_utc, 'HH24') = '04' then router_destination_code else NULL end) as "Hour 5",
count(case when to_char(app_last_updated_date_utc, 'HH24') = '05' then router_destination_code else NULL end) as "Hour 6"
from booker.routing_container_history
where 
app_last_updated_by_module in ('ManualSlam', 'slam')
and app_last_updated_date_utc between 'dec/07/2013 00:00:00' and 'dec/14/2013 00:00:00'
group by 
router_destination_code, 
case when to_char(app_last_updated_date_utc, 'HH24') = '00' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '01' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '02' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '03' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '04' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '05' then router_destination_code else NULL end
order by 
case when to_char(app_last_updated_date_utc, 'HH24') = '00' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '01' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '02' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '03' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '04' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '05' then router_destination_code else NULL end,
count(Router_Destination_code) desc;

输出：

来自GORDON LINOFF的新查询

select router_destination_code, 
sum(case when to_char(app_last_updated_date_utc, 'HH24') = '00' then 1 end) as "Hour 1",
sum(case when to_char(app_last_updated_date_utc, 'HH24') = '01' then 2 end) as "Hour 2",
sum(case when to_char(app_last_updated_date_utc, 'HH24') = '02' then 3 end) as "Hour 3",
sum(case when to_char(app_last_updated_date_utc, 'HH24') = '03' then 4 end) as "Hour 4",
sum(case when to_char(app_last_updated_date_utc, 'HH24') = '04' then 5 end) as "Hour 5",
sum(case when to_char(app_last_updated_date_utc, 'HH24') = '05' then 6 end) as "Hour 6"
from booker.routing_container_history
where 
app_last_updated_by_module in ('ManualSlam', 'slam')
and app_last_updated_date_utc between 'dec/07/2013 00:00:00' and 'dec/14/2013 00:00:00'
group by 
router_destination_code, 
case when to_char(app_last_updated_date_utc, 'HH24') = '00' then 1 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '01' then 2 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '02' then 3 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '03' then 4 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '04' then 5 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '05' then 6 end
order by 
case when to_char(app_last_updated_date_utc, 'HH24') = '00' then 1 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '01' then 2 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '02' then 3 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '03' then 4 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '04' then 5 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '05' then 6 end,
count(Router_Destination_code) desc;

Answer 1

而不是使用count(. . .)使用sum(. . .)，而不是：

sum(case when to_char(app_last_updated_date_utc, 'HH24') = '00'
         then 1 end) as "Hour 1"

编辑：

为了清楚起见，查询应该是：

select router_destination_code, 
       sum(case when to_char(app_last_updated_date_utc, 'HH24') = '00' then 1 end) as "Hour 1",
       sum(case when to_char(app_last_updated_date_utc, 'HH24') = '01' then 1 end) as "Hour 2",
       sum(case when to_char(app_last_updated_date_utc, 'HH24') = '02' then 1 end) as "Hour 3",
       sum(case when to_char(app_last_updated_date_utc, 'HH24') = '03' then 1 end) as "Hour 4",
       sum(case when to_char(app_last_updated_date_utc, 'HH24') = '04' then 1 end) as "Hour 5",
       sum(case when to_char(app_last_updated_date_utc, 'HH24') = '05' then 1 end) as "Hour 6"
from booker.routing_container_history
where app_last_updated_by_module in ('ManualSlam', 'slam') and
      app_last_updated_date_utc between 'dec/07/2013 00:00:00' and 'dec/14/2013 00:00:00'
group by router_destination_code
order by sum(case when to_char(app_last_updated_date_utc, 'HH24') = '00' then 1 end),
         sum(case when to_char(app_last_updated_date_utc, 'HH24') = '01' then 1 end),
         sum(case when to_char(app_last_updated_date_utc, 'HH24') = '02' then 1 end),
         sum(case when to_char(app_last_updated_date_utc, 'HH24') = '03' then 1 end),
         sum(case when to_char(app_last_updated_date_utc, 'HH24') = '04' then 1 end),
         sum(case when to_char(app_last_updated_date_utc, 'HH24') = '05' then 1 end),
         count(Router_Destination_code) desc;