我有这两个表:
接收
id reception_date tin_lot company_id client_id quantity weight
1 2013-12-03 00:00:00 1 1 1 10 1980.00
2 2013-12-03 00:00:00 2 1 1 1 150.00
3 2013-12-13 00:00:00 3 1 2 10 4500.00
4 2013-12-13 00:00:00 4 2 5 5 2300.00
付款
id payment_date amount reception_id
1 2013-12-03 00:00:00 500.0 1
2 2013-12-03 00:00:00 1200.0 3
我想获得的结果如下:
预期结果
id reception_date tin_lot client_id weight payment_made
1 2013-12-03 00:00:00 1 1 1980.00 500.0
2 2013-12-03 00:00:00 2 1 150.00 0.0
3 2013-12-13 00:00:00 3 2 4500.00 1200.0
4 2013-12-13 00:00:00 4 5 2300.00 0.0
我正在尝试此查询:
select rec.id
rec.reception_date,
rec.tin_lot,
rec.client_id,
rec.weight,
pay.payment_made
from liquidation.reception rec, liquidation.payment pay
where pay.recepcion_id=rec.id
但它没有列出没有付款的招待会。
请帮帮我。提前谢谢。
答案 0 :(得分:1)
您需要左加入付款表:
from liquidation.reception rec
left join liquidation.payment pay on ( pay.recepcion_id=rec.id)
答案 1 :(得分:0)
这是因为您需要学习使用left outer join
和正确的连接语法。只是不要在from
子句中使用逗号。
以下是您想要的查询:
select rec.id, rec.reception_date, rec.tin_lot, rec.client_id, rec.weight,
coalesce(pay.payment_made, 0) as payment_made
from liquidation.reception rec left outer join
liquidation.payment pay
on pay.recepcion_id = rec.id;