我正在尝试编写Selenium测试以选择一个单选按钮。以下是'view Source'中的html。
<table id="surveyForm:surveyUrlType" class="ui-selectoneradio ui-widget" style="width:100%;margin-top:10px;margin-bottom: 10px;">
<tbody>
<tr>
<td>
<div class="ui-radiobutton ui-widget">
<div class="ui-helper-hidden-accessible">
<input id="surveyForm:surveyUrlType:0" name="surveyForm:surveyUrlType" type="radio" value="TYPED" checked="checked" onchange="com.ssi.feasibility.surveyView.showSurveyType(this);">
</div>
<div class="ui-radiobutton-box ui-widget ui-corner-all ui-state-default ui-state-active">
<span class="ui-radiobutton-icon ui-icon ui-icon-bullet"></span>
</div>
</div>
</td>
<td><label for="surveyForm:surveyUrlType:0">Enter Survey URL</label></td>
<td>
<div class="ui-radiobutton ui-widget">
<div class="ui-helper-hidden-accessible">
<input id="surveyForm:surveyUrlType:1" name="surveyForm:surveyUrlType" type="radio" value="FILE" onchange="com.ssi.feasibility.surveyView.showSurveyType(this);">
</div>
<div class="ui-radiobutton-box ui-widget ui-corner-all ui-state-default">
<span class="ui-radiobutton-icon"></span>
</div>
</div>
</td>
<td><label for="surveyForm:surveyUrlType:1">Upload Survey URLs</label></td>
</tr>
</tbody>
</table>
我想选择“上传调查网址”单选按钮。
我尝试了几种不同的方法来选择单选按钮。以下是一些:
$("#surveyForm\\surveyUrlType").click();
This gives me the error :
$("#surveyForm\\:surveyUrlType\\:1").first().click()
错误元素在点(809,367)处无法点击。其他元素会收到点击:...
下面给我NoSuchElementFound:
driver.findElement(By.id("surveyForm:surveyUrlType:1")).click()
driver.findElement(By.xpath("//input[@type='radio' and @id='surveyForm\\:surveyUrlType\\:1']")).click()
driver.findElement(By.xpath("//input[@value='FILE']")).click()
driver.findElement(By.cssSelector("#surveyForm\\:surveyUrlType\\:1")).click()
下面没有给我任何错误,但他们也没有选择单选按钮。
$(".ui-radiobutton-box ui-widget ui-corner-all ui-state-default")[1].click()
$(".ui-radiobutton-box ui-widget ui-corner-all ui-state-default").click()
$("#surveyForm\\:surveyUrlType").find(".ui-radiobutton-box ui-widget ui-corner-all ui-state-default").find("span").click()
但这些都不起作用。我错过了什么?
答案 0 :(得分:6)
这就是我最终开始工作的方式!!
driver.findElement(By.cssSelector("label[for='surveyForm\\:surveyUrlType\\:1']")).click()
答案 1 :(得分:0)
尝试
WebElement element = new WebDriverWait(Driver,30).until(ExpectedConditions.elementToBeClickable(By.id("surveyForm:surveyUrlType:1")));
element.click();
答案 2 :(得分:0)
我在Java中有以下代码
lst=driver.findElements(by_name("surveyForm:surveyUrlType"))
for(condition)
option.click()
在python中我用这种方式解决了问题:
lst=driver.find_elements_by_name("surveyForm:surveyUrlType")
for i in lst:
if(i.text=="Enter Survey")
i.click()
elif(i.text=="Upload Survey URLs")
i.click()
如果上述内容没有帮助尝试这个
driver.findElement(by_class_name("ui-radiobutton-icon ui-icon ui-icon-bullet")).click()
driver.findElement(by_class_name("ui-radiobutton-icon")).click()