Question

我的Service类中创建了一个broadcastreceiver。它被设置为对此操作做出反应：WifiManager.SCAN_RESULTS_AVAILABLE_ACTION

所以基本上每次我都做wifi.startScan（）的方法调用; ，结果变得可用，广播接收者的onReceive方法做了它的事情。

我的问题是我需要处理这些扫描结果，并且在广播接收器中做这么多可能不是很好的做法。我想在我的服务类中进行所有计算，但我需要以某种方式访问ScanResults。

对此有何帮助？因为它非常需要。

这是我的代码的简化版本，传达了我的广播接收者的目的：

我的服务类的片段：

        IntentFilter i = new IntentFilter();
        i.addAction(WifiManager.SCAN_RESULTS_AVAILABLE_ACTION); //reacts to the scan results being available

        registerReceiver(mybroadcast,i);

        wifi = (WifiManager) getSystemService(Context.WIFI_SERVICE);
        if(!wifi.isWifiEnabled()){ // if wifi is not enabled
                toast = Toast.makeText(getApplicationContext(), "Wifi is off. Please turn it on.", Toast.LENGTH_LONG);
                toast.show();
                //wifi.setWifiEnabled(true);
                //startActivity(backIntent);

         }

         else
         {
                wifi.startScan(); //what the receiver is going to react to
         }

我的收件人代码：

private final BroadcastReceiver mybroadcast = new BroadcastReceiver() {
           @Override
           public void onReceive(Context context, Intent intent) {
                //gets the scan results
                wifi = (WifiManager) mContext.getSystemService(Context.WIFI_SERVICE);
                List<ScanResult> scans = wifi.getScanResults();
                     // do some work here...
                   }
}

Answer 1

您可以尝试为ex：

添加处理程序

private final Handler handler = new Handler() {

    public void handleMessage(Message msg) {

        String aResponse = msg.getData().getString("message");

        if ((null != aResponse)) {

            // ALERT MESSAGE
            Toast.makeText(getBaseContext(),
                    "Server Response: " + aResponse, Toast.LENGTH_SHORT)
                    .show();
        } else {

            // ALERT MESSAGE
            Toast.makeText(getBaseContext(),
                    "Not Got Response From Server.", Toast.LENGTH_SHORT)
                    .show();
        }

    }
};

并在您的BroadcastReceiver的OnReceive中向其发送消息：

   Message msgObj = handler.obtainMessage();
   Bundle b = new Bundle();
   b.putString("message", msg);
   msgObj.setData(b);
   handler.sendMessage(msgObj);

如何从broadcastreceiver发送扫描结果到服务

1 个答案: