我有一个我写的python函数,它可以使用子进程以root身份运行shell命令。我正在尝试添加功能来检测错误的密码尝试。这是功能。
local_pass = None
def runShellCommandAsRoot(cmd):
global local_pass
if local_pass == None:
print "Enter admin user's password."
local_pass = getpass.getpass()
cmd = "echo {} | sudo -S {}".format(local_pass, cmd)
sp = subprocess.Popen(cmd, shell=True, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
out, err = sp.communicate()
这很好用。我尝试添加以检测失败的密码尝试是解析stderr但我会在每个循环上得到不同的结果。请参阅下面的代码(我尝试添加上面的函数):
for i in range(5):
if err == "Password:Sorry, try again.\nPassword:\nsudo: 1 incorrect password attempt\n":
print "Enter admin user's password."
local_pass = getpass.getpass()
cmd = "echo {} | sudo -S {}".format(local_pass, cmd)
sp = subprocess.Popen(cmd, shell=True, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
out, err = sp.communicate()
elif err == None or err == "":
return out, err
break
if i == 4:
print "Exceeded password attempts."
exit()
答案 0 :(得分:1)
一位朋友帮我找到了运行shell命令的更好解决方案,还包括用户密码的错误检查!见下文:
def run_shell_command_as_root(cmd):
cmd[:0] = ['sudo']
if not authenticate():
print 'Unable to authenticate'
sys.exit(1)
sp = subprocess.Popen(cmd, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
return sp.communicate()
def authenticate():
pwd = ''
for i in range(5):
sp = subprocess.Popen(['sudo', '-S', '-v'], stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
sp.communicate(pwd + '\n')
if sp.returncode == 0:
return True
if i == 0:
print "Please enter user password."
else:
print "Incorrect password. Please try again."
pwd = getpass.getpass()
return False