Question

如何使用select的值插入多个值？我想做这样的事情：

INSERT INTO Table1
    (id, value1, value2)
VALUES
    (id1, 1, 1),
    (id1, 3, 1),
    (id1, 4, 1),
    ...
    (id2, 1, 1),
    (id2, 3, 1),
    (id1, 4, 1),
    ...

但我想从select：

获取id1，id2等

SELECT ID
FROM Table2
WHERE name like '%bla%'

Answer 1

也许就像这样

INSERT INTO Table1
(id, value1, value2)
SELECT ID,value1, value2
FROM Table2
WHERE value1 like '%bla%'

Answer 2

DECLARE @ids AS TABLE(id int not null primary key identity(1,1), targetId int)

INSERT INTO @ids (targetId)
    SELECT ID
    FROM Table2
    WHERE name like '%bla%'

DECLARE @i AS int
DECLARE @n AS int
DECLARE @id AS int

SET @n = (SELECT COUNT(1) FROM @ids)
SET @i = 1

WHILE ( @i <= @n )
BEGIN
    SELECT @id = targetId FROM @ids WHERE id = @i

    INSERT INTO Table1
        (ID, Value1, Value2)
    VALUES
        (@id, 1, 1),
        (@id, 4, 1),
        (@id, 5, 1)

    SET @i = @i + 1
END

SQL使用select的结果插入多个值

2 个答案: