Question

我最近做了这个教程http://www.reinteractive.net/posts/32-ruby-on-rails-3-2-blog-in-15-minutes-step-by-step，但是我很难弄清楚如何在发布评论后删除评论，我已经尝试了

方法但不起作用

它只是向我返回未定义的方法错误，我做错了什么

我的代码：

<%= div_for rep do %>
    <p>
        <div style="font-weight:bold; color:grey;"><%= rep.title %></div>
        <div><%= rep.body %></div>
            <strong style="font-size:8px;">
                    Posted <%= time_ago_in_words(rep.created_at) %> ago
            </strong>
            <br/>
            <%= link_to 'Destroy', steppy_reps_path(@steppy, rep), method: :delete, data: { confirm: 'Are you sure?' } %>
    </p>
<% end %>

错误：没有路线匹配[DELETE]＆＃34; /steppies/11/reps.9"

routes.rb中：

Testapp2::Application.routes.draw do
  resources :steppies do
    resources :reps, :only => [:create]
  end

  get "steppies/ask"
  get "steppies/create"
  get "steppy/ask"
  get "steppy/create"
end

rake route output：

   steppy_reps POST   /steppies/:steppy_id/reps(.:format)     reps#create
    steppy_rep DELETE /steppies/:steppy_id/reps/:id(.:format) reps#destroy
      steppies GET    /steppies(.:format)                     steppies#index
               POST   /steppies(.:format)                     steppies#create
    new_steppy GET    /steppies/new(.:format)                 steppies#new
   edit_steppy GET    /steppies/:id/edit(.:format)            steppies#edit
        steppy GET    /steppies/:id(.:format)                 steppies#show
               PUT    /steppies/:id(.:format)                 steppies#update
               DELETE /steppies/:id(.:format)                 steppies#destroy
  steppies_ask GET    /steppies/ask(.:format)                 steppies#ask
teppies_create GET    /steppies/create(.:format)              steppies#create
    steppy_ask GET    /steppy/ask(.:format)                   steppy#ask
 steppy_create GET    /steppy/create(.:format)                steppy#create

Answer 1

您需要将操作添加到routes.rb文件中。

resources :steppies do
  resources :reps, :only => [:create, :destroy]
end

此外，表单需要使用不同的路径。

steppy_rep_path(@steppy, rep)

如何删除Rails中的嵌套注释

1 个答案: