我们有一个如下所列的课程结构
public class ItemDTO
{
public int ItemID { get; set; }
}
public class CostPageDTO
{
public string CostPageNumber { get; set; }
public List<ItemDTO> Items { get; set; }
}
有两个列表 - 1)数据库中存在的Costpage和Items列表2)用户选择的costpages
问题
我们需要比较这两个列表并获得一个结果列表,其中包含成本页面,实际集合和选定集合中不同项目的计数相同。
这个best performing
LINQ是什么(采用链式方法)?
预期结果
基于以下场景的预期结果是仅包含1个成本页的列表 - “C2”(项目匹配)
CODE
static void Main(string[] args)
{
List<CostPageDTO> selectedCostPageAndItems = GetSelectedCostPageAndItems();
List<CostPageDTO> actualItems = GetActualItems();
//LINQ code to get the matching count costPages
}
private static List<CostPageDTO> GetSelectedCostPageAndItems()
{
ItemDTO i1 = new ItemDTO();
i1.ItemID = 1;
ItemDTO i2 = new ItemDTO();
i2.ItemID = 2;
ItemDTO i3 = new ItemDTO();
i3.ItemID = 3;
CostPageDTO c1 = new CostPageDTO();
c1.CostPageNumber = "C1";
c1.Items = new List<ItemDTO>();
c1.Items.Add(i1);
CostPageDTO c2 = new CostPageDTO();
c2.CostPageNumber = "C2";
c2.Items = new List<ItemDTO>();
c2.Items.Add(i2);
c2.Items.Add(i3);
//CostPageDTO c2Duplicate = new CostPageDTO();
//c2Duplicate.CostPageNumber = "C2";
//c2Duplicate.Items = new List<ItemDTO>();
//c2Duplicate.Items.Add(i2);
//c2Duplicate.Items.Add(i3);
List<CostPageDTO> selectedCostPageAndItems = new List<CostPageDTO>();
selectedCostPageAndItems.Add(c1);
selectedCostPageAndItems.Add(c2);
//selectedCostPageAndItems.Add(c2Duplicate);
return selectedCostPageAndItems;
}
private static List<CostPageDTO> GetActualItems()
{
ItemDTO i1 = new ItemDTO();
i1.ItemID = 1;
ItemDTO i2 = new ItemDTO();
i2.ItemID = 2;
ItemDTO i3 = new ItemDTO();
i3.ItemID = 3;
ItemDTO i3Duplicate = new ItemDTO();
i3Duplicate.ItemID = 3;
CostPageDTO c1 = new CostPageDTO();
c1.CostPageNumber = "C1";
c1.Items = new List<ItemDTO>();
c1.Items.Add(i1);
c1.Items.Add(i2);
c1.Items.Add(i3);
CostPageDTO c2 = new CostPageDTO();
c2.CostPageNumber = "C2";
c2.Items = new List<ItemDTO>();
c2.Items.Add(i2);
c2.Items.Add(i3);
c2.Items.Add(i3Duplicate);
List<CostPageDTO> actualItems = new List<CostPageDTO>();
actualItems.Add(c1);
actualItems.Add(c2);
return actualItems;
}
答案 0 :(得分:4)
这将选择您的预期结果:
方法语法:
var result = selectedCostPageAndItems.SelectMany(scp => actualItems.Where(acp=>acp.CostPageNumber == scp.CostPageNumber),
(scp,acp)=> new {CostPageNumber = scp.CostPageNumber,
scpItems = new HashSet<int>(scp.Items.Select(x=>x.ItemID)),
acpItems = new HashSet<int>(acp.Items.Select(x=>x.ItemID))})
.Where(x => x.scpItems.SetEquals(x.acpItems))
.Select(x => x.CostPageNumber);
查询理解语法:
var result = from cp1 in selectedCostPageAndItems
from cp2 in actualItems
let items1 = new HashSet<int>(cp1.Items.Select(x=>x.ItemID))
let items2 = new HashSet<int>(cp2.Items.Select(x=>x.ItemID))
where cp1.CostPageNumber == cp2.CostPageNumber
&& items1.SetEquals(items2)
select cp1.CostPageNumber;
<强>解释强>
查找具有相同scp
acp
)和实际(CostPageDTO
)CostPageNumber
对
selectedCostPageAndItems.SelectMany(scp => actualItems.Where(acp=>acp.CostPageNumber == scp.CostPageNumber)
对于每对此类对(scp
和acp
),请为所选(CostPageNumber
)和实际(ItemDTO.ItemID
选择scpItems
和一组acpItems
( CostPageDTO
)(scp,acp)=> new {CostPageNumber = scp.CostPageNumber,
scpItems = new HashSet<int>(scp.Items.Select(x=>x.ItemID)),
acpItems = new HashSet<int>(acp.Items.Select(x=>x.ItemID))})
CostPageNumber
最后选择具有相同集合的Where(x => x.scpItems.SetEquals(x.acpItems)).Select(x => x.CostPageNumber)
{{1}}
HashSet
的创建和比较全部是 O(n)