Question

我有一个加载两个radgrids的按钮。第一个是“国家”（快速从db获取数据）。第二个是“城市”（从数据库慢慢获取数据）。在aspx.cs中它看起来像：

grdCities.DataSource = doWork1();
grdCities.DataBind();

grdCountries.DataSource = doWork2();
grdCountries.DataBind();

当相应网格的数据准备就绪时，有没有办法让它们彼此独立地分页？我应该使用服务器端的线程和ajax将其发送到页面以及如何做到这一点吗？

Answer 1

请创建新网页并尝试使用以下代码段。

<强> .ASPX

<!DOCTYPE html>
<html>
<head runat="server">
    <title></title>
    <script src="Script/jquery-1.8.2.js"></script>
    <telerik:RadCodeBlock ID="RadCodeBlock1" runat="server">
        <script>
            $(document).ready(function () {

            });
            function testclick() {

                var ajaxManager = $find("<%= RadAjaxManager1.ClientID %>");
                ajaxManager.ajaxRequest("RadGrid1");
                ajaxManager.ajaxRequest("RadGrid2");

                return false;
            }
        </script>
    </telerik:RadCodeBlock>
</head>
<body>
    <form id="form1" runat="server">
        <telerik:RadScriptManager ID="RadScriptManager1" runat="server"></telerik:RadScriptManager>
        <telerik:RadAjaxManager ID="RadAjaxManager1" runat="server" OnAjaxRequest="RadAjaxManager1_AjaxRequest" RequestQueueSize="10">
            <AjaxSettings>
                <telerik:AjaxSetting AjaxControlID="RadAjaxManager1">
                    <UpdatedControls>
                        <telerik:AjaxUpdatedControl ControlID="RadGrid1" />
                        <telerik:AjaxUpdatedControl ControlID="RadGrid2" />
                    </UpdatedControls>
                </telerik:AjaxSetting>
            </AjaxSettings>
        </telerik:RadAjaxManager>
        <telerik:RadGrid ID="RadGrid1" runat="server"></telerik:RadGrid>
        <telerik:RadGrid ID="RadGrid2" runat="server"></telerik:RadGrid>

        <asp:Button ID="Button1" runat="server" OnClientClick="return testclick();" />
    </form>
</body>
</html>

<强> .ASPX.CS

public partial class Forum : System.Web.UI.Page
{

    protected void Page_Init(object source, System.EventArgs e)
    {



    }

    protected void Page_Load(object sender, EventArgs e)
    {

    }

    private void NewMethod()
    {
        DataTable dt = new DataTable();

        dt.Columns.Add("ID", typeof(int));
        dt.Columns.Add("Name", typeof(string));
        dt.Columns.Add("Custom1", typeof(string));

        dt.Rows.Add(1, "name1", "custom1");
        dt.Rows.Add(2, "name2", "custom2");
        dt.Rows.Add(3, "name3", "Radgrid1_" + DateTime.Now.ToString());

        RadGrid1.DataSource = dt;
        RadGrid1.DataBind();
    }

    private void NewMethod2()
    {
        DataTable dt = new DataTable();

        dt.Columns.Add("ID", typeof(int));
        dt.Columns.Add("Name", typeof(string));
        dt.Columns.Add("Custom1", typeof(string));

        dt.Rows.Add(1, "name1", "custom1");
        dt.Rows.Add(2, "name2", "custom2");
        dt.Rows.Add(3, "name3", "Radgrid2_" + DateTime.Now.ToString());

        RadGrid2.DataSource = dt;
        RadGrid2.DataBind();
    }

    protected void RadAjaxManager1_AjaxRequest(object sender, AjaxRequestEventArgs e)
    {
        if (e.Argument == "RadGrid1")
        {
            NewMethod();
        }
        else if (e.Argument == "RadGrid2")
        {
            Thread.Sleep(5000);
            NewMethod2();
        }
    }
}

如果有任何疑虑，请告诉我。

谢谢， Jayesh Goyani

Telerik在按下的键上加载两个radgrids

1 个答案: