如何在下面的图片中通过示例统一几个相同的数据/数据重复
图片:http://i.stack.imgur.com/L1cHC.jpg
这是我的查询:
SELECT cl.client_group,
cl.NAME,
vw.CLASS,
vw.buscat,
vw.currency,
vw.sum_insured,
vw.client_premium,
vw.net_income,
vw.client
FROM vw_ans_pol_coingrpibs vw, client cl, client_grp cgrp
WHERE (vw.CLIENT = cl.CLIENT(+))
AND (cl.CLIENT_GROUP = cgrp.CLIENT_GROUP(+))
AND vw.CLOSING_DATE BETWEEN TO_DATE('01/01/2007', 'DD/MM/YYYY') AND
TO_DATE('15/01/2007', 'DD/MM/YYYY')
ORDER BY vw.CURRENCY, vw.CLIENT, vw.CLASS
你能帮助我吗?
答案 0 :(得分:0)
如果我能帮到你,你完成了大部分工作,你只需要分组,你就完成了:
SELECT X.NAME, X.CLASS,
SUM(X.sum_insured) sum_insured,
SUM(X.client_premium) client_premium,
SUM(X.net_income) net_income
from
(
SELECT cl.client_group,
cl.NAME,
vw.CLASS,
vw.buscat,
vw.currency,
vw.sum_insured,
vw.client_premium,
vw.net_income,
vw.client
FROM vw_ans_pol_coingrpibs vw, client cl, client_grp cgrp
WHERE (vw.CLIENT = cl.CLIENT(+))
AND (cl.CLIENT_GROUP = cgrp.CLIENT_GROUP(+))
AND vw.CLOSING_DATE BETWEEN TO_DATE('01/01/2007', 'DD/MM/YYYY') AND
TO_DATE('15/01/2007', 'DD/MM/YYYY')
) X
GROUP BY X.NAME, X.CLASS