Question

我正在编译在Clang 3.5计算机上使用Ubuntu 13.04 x86的程序。我想获得在cpp项目中声明的所有变量。这是我写的： -

// Declares clang::SyntaxOnlyAction.
#include "clang/Frontend/FrontendActions.h"
#include "clang/Tooling/CommonOptionsParser.h"
#include "clang/Tooling/Tooling.h"
#include "clang/ASTMatchers/ASTMatchers.h"
#include "clang/ASTMatchers/ASTMatchFinder.h"
// Declares llvm::cl::extrahelp.
#include "llvm/Support/CommandLine.h"
#include "clang/AST/DeclCXX.h"
#include <iostream>
#include <vector>

using namespace clang::tooling;
using namespace llvm;
using namespace clang::ast_matchers;
using namespace clang;
using namespace std;

static cl::extrahelp CommonHelp(CommonOptionsParser::HelpMessage);

static cl::extrahelp MoreHelp("\nMore help text...");

static cl::OptionCategory MyToolCategory("My Tool Category");

internal::Matcher<Decl> fields = fieldDecl().bind("field");
internal::Matcher<Decl> params = parmVarDecl().bind("param");
internal::Matcher<Decl> vars = varDecl().bind("var");

class VarDeclPrinter : public MatchFinder::MatchCallback {
  public:
  int counter;

  virtual void run(const MatchFinder::MatchResult &Result) {
    const Decl* dec;

    if(const FieldDecl* field = Result.Nodes.getNodeAs<FieldDecl>("field"))
      llvm::outs() << "Member Variable: " << field->getName() << "\t\t" 
                   << field->getParent()->getQualifiedNameAsString() << "\n";

    if(const ParmVarDecl* param = Result.Nodes.getNodeAs<ParmVarDecl>("param"))
      llvm::outs() << "Argument Variable: " << param->getName() << "\t\t"
                   << ((CXXMethodDecl*)(param->getParentFunctionOrMethod()))->getQualifiedNameAsString() << "\n";

    if(const VarDecl* var = Result.Nodes.getNodeAs<VarDecl>("var"))
      llvm::outs() << "Local Variable: " << var->getName() << "\t\t"
                   << ((CXXMethodDecl*)(var->getParentFunctionOrMethod()))->getQualifiedNameAsString() << "\n";

    counter++;
    //llvm::outs() << "Variable count: " << counter << "\n";
    //ASTContext* Context = Result.Context;
  }
};

int main(int argc, const char **argv) {
  CommonOptionsParser OptionsParser(argc, argv, MyToolCategory);
  ClangTool Tool(OptionsParser.getCompilations(),
                 OptionsParser.getSourcePathList());

  VarDeclPrinter VarDeclCallback;
  MatchFinder Finder;

  Finder.addMatcher(fields, &VarDeclCallback);
  Finder.addMatcher(params, &VarDeclCallback);
  Finder.addMatcher(vars, &VarDeclCallback);
  return Tool.run(newFrontendActionFactory(&Finder));
}

当我尝试运行此程序时，我得到分段错误（可能在我将var->getParentFunctionOrMethod()投射到CXXMethodDecl*时）。如果它是局部变量，我想要声明此变量的方法名称。任何人都可以告诉我错误的原因是什么？或者什么是更好的方法来获取变量的方法名称？

Answer 1

我得到了解决方案。这是因为我试图获取方法名称，即使var不在方法内。这是解决方案： -

if(const VarDecl* var = Result.Nodes.getNodeAs<VarDecl>("var")) {
  llvm::outs() << "Local Variable: " << var->getName() << "\t\t";
  if(var->isFunctionOrMethodVarDecl())
    llvm::outs() << ((CXXMethodDecl*)(var->getParentFunctionOrMethod()))->getQualifiedNameAsString();
  llvm::outs() << "\n";
}

CLang prog分段错误（（CXXMethodDecl *）（VarDecl-＆gt; getParentFunctionOrMethod（）））

1 个答案: