我有一份清单。我想得到每个列表的子项的id。如果没有子项,那么主要列表的ID,即在我想要gwt region,country and state
的位置下,在设备gateway_unit, meter_unit
下,因为{{1下没有子项}和global parameters
,因此需要有ID。
user
这就是我正在做的事情。我哪里错了?
<ul class="nav nav-pills nav-stacked navigation" id="configuration_sidebar_content">
<li>
<a>Location</a>
<ul class="nav nav-pills nav-stacked " id="location" style="padding-left:30px;">
<li class="active" id="Region"><a href="#region">Region</a></li>
<li id="country"><a href="#country">Country</a></li>
<li id="state"><a href="#state">State</a></li>
</ul>
</li>
<li id="device">
<a>Device</a>
<ul class="nav nav-pills nav-stacked" style="padding-left:30px;">
<li id="gateway_unit"><a href="#gateway-unit">Gateway Unit</a></li>
<li id="meter_unit"><a href="#meter-unit">Meter Unit</a></li>
</ul>
</li>
<li id="user"><a href="#user">Software User</a></li>
<li id="global_parameters"><a href="#global-parameters">Global Parameters</a></li>
</ul>
答案 0 :(得分:0)
$(function(){
$('#configuration_sidebar_content').on('click', 'li a', function(){
var selected_id = $(this).parent().attr('id');
alert(selected_id)
});
});
答案 1 :(得分:0)
$(function () {
$('#configuration_sidebar_content').on('click', 'li', function (e) {
e.stopPropagation();
var children = $(this).find("li");
var ids;
if (children.length) {
ids = $.makeArray(children.map(function () {
return this.id;
}));
} else {
ids = [this.id];
}
alert(ids.join(', '));
});
});