如果用户输入除数字以外的任何数字,除了数字范围为1 - 32之外的任何数字,我还需要它再次请求输入。
当我在1..32
中使用cut_number时,它会给我一个错误def cut_the_deck
puts "You get to cut the deck to make it even more random!"
puts "Type a number between 1 and 32. That's where the deck will be cut!"
cut_number = gets.chomp
cut_number = cut_number.to_i
if cut_number in 1..32
puts "Number in range"
else
puts "Number NOT in range"
cut_the_deck
end
end
答案 0 :(得分:3)
使用between?:
if cut_number.between?(1,32) #=> true or false
答案 1 :(得分:2)
或者你可以这样做:
if (1..32).include?(cut_number)