我正在编写一个打印一个数组的程序,该数组包含作为参数传递的两个数组的值之和。当其中一个数组可能比另一个数组长时,我需要包含异常。在这种情况下,该方法应该打印两个数组共享的索引的总和,然后打印没有要添加的相应值的数组的值。
当我运行程序时,它会计算应该的总和,但是然后打印0.0而不是我想要重新打印的较长数组中的原始值。任何人都知道我的代码中我做错了什么?
import java.util.*;
class Sum
{
public static void main (String [] args)
{
double [] a1 = {2.4, 3.8};
double [] a2 = {0.2, 9.2, 4.3, 2.8, 1.4};
System.out.println (Arrays.toString (arraySum(a1,a2)));
}
public static double [] arraySum (double [] x, double [] y)
{
int length = 0;
int place = 0;
if (x.length < y.length)
{
double [] sumY = new double [y.length];
length = y.length;
for (int j = 0; j <= x.length-1; j++)
{
sumY [j] = x[j] + y[j];
place++;
}
for (int i = place; i <= y.length - 1; i++)
{
sumY [place] = y[i];
}
return sumY;
}
if (x.length > y.length)
{
double [] sumX = new double [x.length];
length = x.length;
for (int j=0; j <= y.length-1; j++)
{
sumX[j] = x[j] + y[j];
place++;
}
for (int i = place; i <= x.length - 1; i++)
{
sumX [place] = y[i];
}
return sumX;
}
else
{
double [] sum = new double [x.length];
length = x.length;
for (int i = 0; i <= length - 1; i++)
{
sum[i] = x[i] + y[i];
}
return sum;
}
}
}
答案 0 :(得分:4)
将sumX [place] = y[i];
更改为sumX [i] = y[i];
。
答案 1 :(得分:1)
您未在后续place
循环中递增for
。
for (int i = place; i <= x.length - 1; i++)
{
sumX [place] = y[i];
place++;
}
答案 2 :(得分:0)
你的if else构造看起来很可疑。似乎最后一个在你的情况下执行但不应该......
答案 3 :(得分:0)
整个arraySum
方法有很多可以删除的重复代码,这会使方法更清晰,更容易理解,并且不太可能出错。
public static double [] arraySum (double [] x, double [] y)
{
int length = Math.max(d.length, y.length);
double[] result = new double[length]; // initializes all values to 0
for (int i=0;i<length;i++) {
if (i<x.length)
result[i] = x[i]; // if x is this length use its value instead of 0
if (i<y.length)
result[i] += y[i]; // if y is this length add its value to the sum
}
return result;
}
这就是你所需要的......