Question

只需在牌组中使用2-9。

在Ruby中创建套牌的首选和/或最有效方法是什么？

这是我下面的内容，或者我该怎么做/应该这样做？

deck = []
suits = ["spades", "diamonds", "clubs", "hearts"]

for x in suits
  for y in 2..9
    w = y.to_s
    deck.push(w+" of "+x)
  end
end

Answer 1

我喜欢product w / a block

a, suits = [], ["spades", "diamonds", "clubs", "hearts"]
suits.product((2..9).to_a) {|t,n| a << "#{n} of #{t}"}

Answer 2

嗯，你可以使用地图：

suits = ["spades", "diamonds", "clubs", "hearts"]
deck = suits.map { |d| (2..9).map { |x| "#{x} of #{d}" } }.flatten

但效率大致相同。

Answer 3

suits = ["spades", "diamonds", "clubs", "hearts"]
deck = suits.product((2..9).to_a).map { |x,y| "#{y} of #{x}" }

如果您想要所有52张卡片：

suits = ["spades", "diamonds", "clubs", "hearts"]
faces = { 1 => 'Ace', 11 => 'Jack', 12 => 'Queen', 13 => 'King' }
deck = suits.product((1..13).to_a).map { |x,y| "#{faces[y]||y} of #{x}" }
# => Ace of spades, 2 of spades, ..., King of spades, Ace of diamonds, etc.

Answer 4

怎么样：

suits.flat_map {|s| (2..9).map{|r| "#{r} of #{s}"}}

Answer 5

suits, values, deck = %w(spades hearts diamonds clubs), [*2..9], values.product(suits).map { |card| card * ' of ' }

在Ruby中创建列表的更有效方法

5 个答案: