Question

我正在尝试用MySQL数据库中的数据制作一个简单的饼图。我有两个问题，

$males="SELECT COUNT(JudgeGender) FROM case_info WHERE JudgeGender='M'";
$females="SELECT COUNT(JudgeGender) FROM case_info WHERE JudgeGender='F'";

这些存储了db

中有多少男性和女性的值

然后我试图在谷歌饼图中使用它们

<!--Load the AJAX API-->
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript">

// Load the Visualization API and the piechart package.
google.load('visualization', '1.0', {'packages':['corechart']});

// Set a callback to run when the Google Visualization API is loaded.
google.setOnLoadCallback(drawChart);

// Callback that creates and populates a data table,
// instantiates the pie chart, passes in the data and
// draws it.
function drawChart() {

// Create the data table.
var data = new google.visualization.DataTable();
data.addColumn('string', 'Gender');
data.addColumn('number', 'Number');
data.addRows([  
    ['Male', <?php echo $males; ?>],
    ['Female', <?php echo $females; ?>]
    ]);

// Set chart options
var options = {'title':'Judge Gender Breakdown',
                       'width':500,
                       'height':400};

// Instantiate and draw our chart, passing in some options.
var chart = new google.visualization.PieChart(document.getElementById('chart_div'));
chart.draw(data, options);
      }
  </script> 
  </head>

  <body>
    <!--Div that will hold the pie chart-->
    <div id="chart_div"></div>
  </body>
</html>

图表没有画出来。我错过了什么吗？我有一种感觉，这是由于数据类型不匹配，但我不确定。

谢谢！

使用SQL中的PHP变量创建Google Visualization图表

0 个答案: