Question

这是我使用的查询工作正常，但我希望结果集按字母顺序排列在同一列中出现的第二个值。

SELECT userid 
FROM my_table 
WHERE value = $corrected_gradyear
and attributeid = 4

表格设置就像这样

attributeid userid value
3           1231   maidenname
2           1231   lastname
4           1231   1980
5           1231   address
8           1231   phone
9           1231   email
3           5      maidenname
2           5      lastname
4           5      1978
5           5      address
8           5      phone
9           5      email

我只想要用户ID ID，但我希望它们按属性3（婚前姓名）按字母顺序排序。

Answer 1

这是你想要的吗？

select t1.userid,t1.value as year,t2.value as maidenname from my_table t1
join my_table t2 on t2.userid = t1.userid and t2.attributeid=3
where t1.attributeid=4
order by t1.value,t2.value

Answer 2

这只是一张可怕的桌子。

我猜你要做的是：

SELECT VALUE as MaidenName
FROM my_table WHERE attributeID = 3
AND UserID IN 
(SELECT userid 
   FROM my_table 
   WHERE value = $corrected_gradyear
   and attributeid = 4)
ORDER BY MaidenName

Answer 3

SELECT tUsers.userid 
FROM my_table tUsers
INNER JOIN my_table tMaidenNames ON tMaidenNames.userid = tUsers.userid AND tMaidenNames.attributeid = 3
WHERE tUsers.value = $corrected_gradyear
AND tUsers.attributeid = 4
ORDER BY tMaidenNames.value ASC

http://sqlfiddle.com/#!2/9dc63/2

Answer 4

SELECT userid 
     , MAX(CASE WHEN  attributeid = 4 THEN value END) corrected_grad_year
     , MAX(CASE WHEN  attributeid = 3 THEN value END) maidenname 
  FROM eav_hell 
 GROUP 
    BY userid
 ORDER
    BY whatever;

选择单个值，但对同一列中出现的另一个值进行排序

4 个答案: