我正在使用Unity Mvc4软件包,它有一个在Application Start
上运行的bootstrap类(如下所示)如何在不使用脏的静态属性的情况下访问我的容器?
public static class Bootstrapper
{
public static IUnityContainer Container { get; set; }
public static IUnityContainer Initialise()
{
Container = BuildUnityContainer();
DependencyResolver.SetResolver(new UnityDependencyResolver(Container));
return Container;
}
private static IUnityContainer BuildUnityContainer()
{
var container = new UnityContainer();
// register all your components with the container here
// it is NOT necessary to register your controllers
// e.g. container.RegisterType<ITestService, TestService>();
RegisterTypes(container);
RegisterInstances(container);
return container;
}
public static void RegisterTypes(IUnityContainer container)
{
container.RegisterType<IDataAccessHelper, DataAccessHelper>();
}
public static void RegisterInstances(IUnityContainer container)
{
container.RegisterInstance<GlobalHelper>(new GlobalHelper());
}
}