Question

我的profileTable中有一个名为“Associations”的列...我正在尝试查询与关联相关的配置文件。

$sql = mysqli_query($con,"SELECT * FROM profileTable  WHERE  Keyword_ID LIKE
'%".$getKeyID."%' ORDER BY  Associations <> 'School of Engineering 
and Computer Science', Associations AND LaName ASC LIMIT $start,$end");

我可以通过教育索引个人资料，但不能通过协会索引。

    while ($row = mysqli_fetch_array($sql)) {
        $key = $row['Keyword_Name'];
        $keyID = $row['Keyword_ID'];
        $fname = $row['FirName'];
        $lname = $row['LaName'];
        $mname = $row['MName'];
        $suffix = $row['Suffix'];
        $title = $row['Title'];
        $title2 = $row['Title2'];
        $title3 = $row['Title3'];
        $education = $row['Education'];
        $education2 = $row['Education2'];
        $education3 = $row['Education3'];
        $dept = $row['Dept'];
        $phone1 = $row['PH1'];
        $phone2 = $row['PH2'];
        $email = $row['Email'];
        $photo = $row['Photo'];
        $bio = $row['BioLK'];
        $website = $row['Website'];
        $assocs = $row['Associations'];

$actions=array('School of Engineering and Computer Science'=>'Computer Science 
       and Engineering');

我需要将关联与$ key（单词）相关联，因此如果用户点击关键词“计算机”，它将与“工程与计算机科学学院”相关联，并将其归入“工程与计算机学院”科学“第一。

这适用于像“教育”这样的其他列，但似乎无法使用我的关联数组。有什么想法吗？

示例sqlfiddle：http://sqlfiddle.com/#!2/c1802/7/0

Answer 1

以下查询列出了根据需要排序的输出。

SELECT * FROM mediaContacts ORDER BY  associations DESC,lname ASC

Fiddle

由于associations有School of Engineering and Computer Science作为最后的Alpha记录，所以

如果School of Engineering and Computer Science不是最后一个alpha记录，则失败并需要另一种方法。

Answer 2

您可以尝试以下

更改

while ($row = mysqli_fetch_array($sql)) {

到

while ($row = mysql_fetch_assoc($sql)) {

它将返回一个与获取的行对应的关联数组，并将内部数据指针向前移动。

在PHP / MySQL查询中创建关联数组

2 个答案: