这个PHP脚本的等效C#语法是什么?:
<?php
$arr = array("linux", "windows", "linux", "linux", "windows", "mac os", "unix", "mac os");
$unique = array_unique($arr);
foreach($unique as $key=>$value){
echo $key."\n";
}
?>
上面代码的结果是:
0
1
5
6
因此,删除了数组的副本,然后显示数组的键。我只能显示数组的值:
string[] arr = { "linux", "windows", "linux", "linux", "windows", "mac os", "unix", "mac os" };
string[] uniq = arr.Distinct().ToArray();
foreach (string unik in uniq)
{
textBox1.AppendText(unik+"\r\n");
}
答案 0 :(得分:5)
你可以很容易地使用Linq做到这一点:
var indices = arr.Distinct()
.Select(s => Array.IndexOf(arr,s));
foreach (int i in indices)
{
textBox1.AppendText(i+"\r\n");
}
或包含值和索引:
var indices = arr.Distinct()
.Select(s => new {s, i = Array.IndexOf(arr,s)});
foreach (var si in indices)
{
textBox1.AppendText(string.Format({0}: {1}\n", si.i, si.s));
}
如果性能是一个问题,那么更有效(虽然难以理解)版本将是:
var indices = arr.Select((s, i) => new {s, i}) // select the value and the index
.GroupBy(si => si.s) // group by the value
.Select(g => g.First()); // get the first value and index
foreach (var si in indices)
{
textBox1.AppendText(string.Format({0}: {1}\n", si.i, si.s));
}
答案 1 :(得分:1)
它对我有用:
string[] arr = { "linux", "windows", "linux", "linux", "windows", "mac os", "unix", "mac os" };
string[] uniq = new string[0];
string[] keys = new string[0];
for (int i = 0; i < arr.Length; i++)
{
if (uniq.Contains(arr[i]))
{
continue;
}
else
{
uniq = uniq.Concat(new string[] { arr[i] }).ToArray();
keys = keys.Concat(new string[] { i + "" }).ToArray();
}
}
foreach (string key in keys)
{
textBox1.Append(key + "\r\n");
}
答案 2 :(得分:0)
这里的LinQ解决方案 - res包含“array”字符串数组中第一次出现的索引:
string[] arr = { "linux", "windows", "linux", "linux", "windows", "mac os", "unix", "mac os" };
var res = arr.Select((value, index) => new { value, index })
.ToDictionary(pair => pair.index, pair => pair.value)
.GroupBy(x => x.Value)
.Select(x => x.First().Key);
foreach (int i in res)
{
textBox1.AppendText(i+"\r\n");
}