我希望能够输入字符串s
和整数n
,然后打印字符串s
n
次。我已经这样做了,但我希望每行只有2个字符串。
到目前为止,这是我的代码:
public static void main(String[]args){
Scanner in = new Scanner(System.in);
System.out.println("Please enter string: ");
String s = in.nextLine();
System.out.println("Please enter number: ");
int n = in.nextInt();
for(int j=0; j<n; j++){
System.out.println(s);
}
if(n<0){
System.out.println("error: number must be positive");
}
}
我们说字符串为java
,数字为6
。我需要输出:
java java
java java
java java
答案 0 :(得分:3)
使用模运算符(%)检查循环索引是否可被2整除。
public static void main(String[]args){
Scanner in = new Scanner(System.in);
System.out.println("Please enter string: ");
String s = in.nextLine();
System.out.println("Please enter number: ");
int n = in.nextInt();
for(int j=1; j<n+1; j++){
System.out.print(s);
if (j%2==0)
System.out.println("\n");
else
System.out.print(" ");
}
if(n<0){
System.out.println("error: number must be positive");
}
}
编辑我将输出更改为使用print()
而不是println()
并添加了一个空格,因此输出格式化为您问题中的示例。还将for循环索引更改为一个,以便mod正常工作。
答案 1 :(得分:0)
在for循环中创建一个计数为2的简单计数器。到达两个之后。添加返回字符。
int count = 0;
for(int j=0; j<n; j++){
System.out.print(s);
count++;
if (count == 2) {
System.out.print("\n");
count = 0;
}
}
答案 2 :(得分:0)
public static void main(String[]args){
Scanner in = new Scanner(System.in);
System.out.println("Please enter string: ");
String s = in.nextLine();
System.out.println("Please enter number: ");
int n = in.nextInt();
for(int j=0; j<n; j++){
// modified
if(j%2==0 && j!=0){
System.out.println("\n");
}
System.out.print(s); // Should this not be print and not println
System.out.print(" ");
// end of modification
}
if(n<0){
System.out.println("error: number must be positive");
}
}
答案 3 :(得分:0)
for(int j=0; j<n/2; j++){
System.out.println(s+" "+s);
}
答案 4 :(得分:0)
试试此代码
public static void main(String[]args){
Scanner in = new Scanner(System.in);
System.out.println("Please enter string: ");
String s = in.nextLine();
System.out.println("Please enter number: ");
int n = in.nextInt();
for(int j=0; j<n/2; j++){
System.out.print(s + " " + s + "\n");
}
if(n%2 == 1){
System.out.print(s);
}
if(n<0){
System.out.println("error: number must be positive");
}
}