在我的应用程序中,我试图仅根据loss_report的两个属性显示activerecord对象数组(loss_reports)的唯一元素。
架构
class Agent < ActiveRecord::Base
has_many :loss_reports, :through => policy
end
class LossReport < ActiveRecord::Base
belongs_to :agent
end
我首先尝试覆盖eql?和LossReport的哈希方法,以便我可以做类似的事情:
选项1:
class LossReport ...
def eql? other
self.policy_id == other.policy_id && loss_occurred_on.hash == self.loss_occurred_on
end
def hash
policy_id + loss_occurred_on.hash
end
end
class Agent ...
def unique_losses
loss_reports.to_set
end
end
但很快删除了代码,因为ActiveRecord已经覆盖了这些方法,而且我不确定是否会产生影响。
选项2:
class Agent ...
def unique_losses
loss_reports.sort{|l1,l2| l2.created_at <=> l1.created_at}.group_by{|l| (l.policy_id + l.loss_occurred_on.hash)}.collect{|hl| hl[-1].first}
end
end
选项3:
class Agent
def unique_losses
hsh_array = []
unique = []
loss_reports.sort{|l1,l2| l2.created_at <=> l1.created_at}.each do |l|
unique << l unless hsh_array.include?(l.hsh)
hsh_array << l.hsh
end
unique
end
end
基准测试结果:
Benchmark.bmbm do |bm|
bm.report("option 2") do
losses.sort{|l1,l2| l2.created_at <=> l1.created_at}.group_by{|l| (l.policy_id + l.loss_occurred_on.hash)}.collect{|hl| hl[-1].first}
end
bm.report("option 3") do
hsh_array,unique = [],[]
losses.sort{|l1,l2| l2.created_at <=> l1.created_at}.each do |l|
unique << l unless hsh_array.include?(l.policy_id+l.loss_occurred_on.hash)
hsh_array << l.policy_id + l.loss_occurred_on.hash
end
end
end
Rehearsal --------------------------------------------
option 2 0.400000 0.000000 0.400000 ( 0.407615)
option 3 0.250000 0.000000 0.250000 ( 0.254399)
----------------------------------- total: 0.650000sec
user system total real
option 2 0.400000 0.000000 0.400000 ( 0.403535)
option 3 0.250000 0.000000 0.250000 ( 0.262578)
两种方式都不对,但两者都有效。哪个是最好的选择还是有更好的方法?
答案 0 :(得分:1)
我不知道基准测试,但似乎inject
是最简单的方法:
loss_reports.inject([]) do |arr, report|
arr << report unless arr.detect{|r| ... }
end
或者更好的方法是用...定义带有自定义SQL组的named_scope。