Question

我有这个观点1

    SELECT min(l.id) AS id, 
    to_char(l.date::timestamp with time zone, 'YYYY:IW'::text) AS name, 
    sum(l.debit - l.credit) AS balance, sum(l.debit) AS debit, 
    sum(l.credit) AS credit, a.type, cumulative_balance
    FROM account_move_line l
    LEFT JOIN account_account a ON l.account_id = a.id
    WHERE l.state::text <> 'draft'::text
    GROUP BY to_char(l.date::timestamp with time zone, 'YYYY:IW'::text), a.type;

和View2

   SELECT min(l.id) AS id, 
   to_char(l.date::timestamp with time zone, 'YYYY:IW'::text) AS name, 
   sum(l.debit - l.credit) AS balance, sum(l.debit) AS debit, 
   sum(l.credit) AS credit, a.type, DATE 'yesterday'
   FROM account_move_line l
   LEFT JOIN account_account a ON l.account_id = a.id
   WHERE l.state::text <> 'draft'::text AND l.date = DATE 'yesterday'
   GROUP BY to_char(l.date::timestamp with time zone, 'YYYY:IW'::text), a.type;

SELECT min(l.id) AS id, 
to_char(l.date::timestamp with time zone, 'YYYY:IW'::text) AS name, 
sum(l.debit - l.credit) AS balance, sum(l.debit) AS debit, 
sum(l.credit) AS credit, a.type, DATE 'today'
FROM account_move_line l
LEFT JOIN account_account a ON l.account_id = a.id
WHERE l.state::text <> 'draft'::text AND l.date = DATE 'today'
GROUP BY to_char(l.date::timestamp with time zone, 'YYYY:IW'::text), a.type;

我希望将view2中的列balance和view1中的列cumulative_balance以及此列cumulative_balance中的列{{1}}加入view2.balance和view3.balance

Answer 1

这是最终得到的解决方案，注意view2和view3是表t和y，这是view1

SELECT yesterday.yesterday, today.today, report.id, report.balance, 
    report.debit, report.credit, cumulative.cumulative, report.name
   FROM ( SELECT y.balance AS yesterday
           FROM report_account_receivable_yesterday) yesterday, 
    ( SELECT t.balance AS today
           FROM report_account_receivable_today) today, 
    ( SELECT sum(y.balance + t.balance) AS cumulative
           FROM report_account_receivable_yesterday y, 
            report_account_receivable_today t) cumulative, 
    ( SELECT min(l.id) AS id, 
            to_char(l.date::timestamp with time zone, 'YYYY:IW'::text) AS name, 
            sum(l.debit - l.credit) AS balance, sum(l.debit) AS debit, 
            sum(l.credit) AS credit, a.type, DATE 'now()' - interval '1 day' AS tarehe
           FROM account_move_line l
      LEFT JOIN account_account a ON l.account_id = a.id
     WHERE l.state::text <> 'draft'::text AND l.date = DATE 'now()' - interval '1 day'
     GROUP BY to_char(l.date::timestamp with time zone, 'YYYY:IW'::text), a.type) report
  ORDER BY report.id DESC;

在postgresql中的不同视图中加入两个具有相同名称的列，并获得总数

1 个答案: