Question

我尝试反序列化对象并获取System.NullReferenceException。我无法找到异常被触发的地方以及异常的原因。

我尝试像这样反序列化：

public static List<T> Get<T>()
{
    string path = GetFilePath (typeof(T));
    List<T> list;
    using (StreamReader stream = new StreamReader (path)) 
    {
        XmlSerializer serializer = new XmlSerializer (typeof(List<T>));                     
        list = (List<T>)serializer.Deserialize (stream);                        
    }
    return list;
}

栈跟踪

在System.Xml.Serialization.XmlSerializationReader.OnUnknownNode上（System.Xml.XmlNode节点，System.Object o，System.String qnames） [0x00000] in：0 at System.Xml.Serialization.XmlSerializationReader.UnknownNode （System.Object o，System.String qnames）[0x00000] in：0 at System.Xml.Serialization.XmlSerializationReader.UnknownNode （System.Object o）[0x00000] in：0 at System.Xml.Serialization.XmlSerializationReaderInterpreter.ReadListElement （System.Xml.Serialization.XmlTypeMapping typeMap，Boolean isNullable， System.Object list，Boolean canCreateInstance）[0x00000] in：0 at System.Xml.Serialization.XmlSerializationReaderInterpreter.ReadObject （System.Xml.Serialization.XmlTypeMapping typeMap，Boolean isNullable， Boolean checkType）[0x00000] in：0 at System.Xml.Serialization.XmlSerializationReaderInterpreter.ReadRoot （System.Xml.Serialization.XmlTypeMapping rootMap）[0x00000] in ：0点 System.Xml.Serialization.XmlSerializationReaderInterpreter.ReadRoot（） [0x00000] in：0 at System.Xml.Serialization.XmlSerializer.Deserialize （System.Xml.Serialization.XmlSerializationReader reader）[0x00000] in ：0

Answer 1

您粘贴的XML无效。我尝试将其粘贴到记事本中，保存为test.xml并在Chrome中打开。看起来它不喜欢分号。我带他们离开我，下面打开了很好：

<?xml version="1.0" encoding="utf-8"?>
<ArrayOfBusinessOffer xmlns:xsi="w3.org/2001/XMLSchema-instance" xmlns:xsd="w3.org/2001/XMLSchema">
<BusinessOffer>
</BusinessOffer>
</ArrayOfBusinessOffer>

Xamarin：在尝试反序列化对象时出现System.Nullreferenceexception

1 个答案: