Question

我正在尝试在解雇另一个对话框后直接显示对话框。

@Override
public void onLoginFailure(Exception e, boolean ttl) {
    if(DialogUtils.isDialogShowing()){
        //dismisses progress dialog
        DialogUtils.DIALOG.dismiss();
    }
    DialogUtils.showExceptionDialog(this, "TTL Expired.");
}

DialogUtils.java：

public volatile static Dialog DIALOG;

public static boolean isDialogShowing() {
    return (DIALOG!=null && DIALOG.isShowing());
}

public static Dialog showExceptionDialog(final Context ctx, final String message) {
    AlertDialog.Builder builder = new AlertDialog.Builder(ctx);
    builder.setTitle(R.string.exception_title);
    builder.setMessage(message);
    builder.setPositiveButton(R.string.button_ok, new DialogInterface.OnClickListener() {
        @Override
        public void onClick(DialogInterface dialogInterface, int i) {
            dialogInterface.cancel();
        }
    });
    if(isDialogShowing()) {
        DIALOG.dismiss();
    }
    DIALOG = builder.create();
    DIALOG.show();
    return DIALOG;
}

public static Dialog showLoggingInProgressDialog(final Context ctx, final boolean cancellable) {
    AlertDialog.Builder builder = new AlertDialog.Builder(ctx);
    builder.setCancelable(cancellable);
    builder.setTitle(R.string.dialog_login_title);
    //ProgressBar pb = new ProgressBar(ctx);
    //pb.setIndeterminate(true);
    //builder.setView(pb);
    if(isDialogShowing()) {
        DIALOG.dismiss();
    }
    DIALOG = builder.create();
    DIALOG.show();
    return DIALOG;
}

在此代码中，当调用onLoginFailure时，将显示“正在登录...”进度对话框。我尝试关闭该对话框以显示错误对话框，但在新对话框上调用.show（）会冻结该应用程序。我做错了什么？

更新（2013年12月16日8:53）：更改要执行失败的操作不会冻结应用程序，但Toast文本永远不会显示...？

@Override
public void onLoginFailure(Exception e, boolean ttl) {
    if(DialogUtils.isDialogShowing()){
        DialogUtils.DIALOG.dismiss();
    }
    if(ttl)
        //DialogUtils.showExceptionDialog(this, "TTL Expired.");
        Toast.makeText(this, "Login failed:\nTTL Expired...", Toast.LENGTH_SHORT);
    else if(e!=null)
        //DialogUtils.showExceptionDialog(this, e);
        Toast.makeText(this, "Login failed:\n" + e.getMessage(), Toast.LENGTH_SHORT);
}

Answer 1

while(isDialogShowing()) {
    //
}

您正在运行无限循环？

Answer 2

替换

while(isDialogShowing()) {
    //
}
DIALOG = builder.show();

带

if(isDialogShowing) {
    DIALOG.dismiss();
}
DIALOG = builder.create();
DIALOG.show();

在show .... Dialog（....）方法......

Android在解除另一个对话框冻结应用程序后直接调用Dialog.show（）

2 个答案: