Question

我正在创建一个比较两个数组的程序;第一个数组，用户输入5个整数。在第二个数组中，计算机随机选择5个数字（两个数组都在0和9之间）。

我需要比较每个数组的元素以查看它们是否匹配。如果它们匹配，我将1添加到计数器变量。

（例如用户输入0 2 2 9 6，计算机[使用rand]选择2 3 2 9 0. elemnts 3＆amp; 4匹配，这样两个。现在每个匹配都有不同的场景）

我的问题：用户还输入他们想要比较这些数组的次数（这是一款名为pick 5的游戏）。 我需要计数器在每次循环时重置为零我尝试使用flush命令，但它不起作用。

任何想法？

int main ()
{
string name;
float total_amt, bet_amt, win_amt;
int play_amt, user_choice[5] = { }, com_choice[6], i, total=0;
int size = 5;

srand((unsigned)time(0));

cout<<"Welcome to pick 5, where the odds are never in your favor!"<<endl;
cout<<"What is your name?"<<endl;
cin>>name;
cout<<"How much money do you have?"<<endl;
cin>>total_amt;
cout<<"How much money would you like to bet?"<<endl;
cin>>bet_amt;
cout<<"How many times would you like to play?"<<endl;
cin>>play_amt;

for (i=0;i<play_amt;i++)
{ 
    cout<<"Pick 5 integers between 0 & 9 "<<endl;

    cin>>user_choice[0];
    cin>>user_choice[1];
    cin>>user_choice[2];
    cin>>user_choice[3];
    cin>>user_choice[4];

    com_choice[0] = (rand()%9);
    com_choice[1] = (rand()%9);
    com_choice[2] = (rand()%9);
    com_choice[3] = (rand()%9);
    com_choice[4] = (rand()%9);

    cout<<com_choice[0];
    cout<<com_choice[1];
    cout<<com_choice[2];
    cout<<com_choice[3];
    cout<<com_choice[4];



    if (user_choice[0]==com_choice[0])
    {
        total++;
    }
    if (user_choice[1]==com_choice[1])
    {
        total++;
    }
    if (user_choice[2]==com_choice[2])
    {
        total++;
    }
    if (user_choice[3]==com_choice[3])
    {
        total++;
    }
    if (user_choice[4]==com_choice[4])
    {
        total++;
    }

    cout<<"User matched "<<total<<"times"<<endl;


    // scenarios
    if (total>=0 &&total<3)
    {
        total_amt-=bet_amt;
        cout<<"Less than 3 of your numbers matched, tough luck"<<endl;
        cout<<"You now have $"<<total_amt<<"dollars left."<<endl;
    }
        else if (total == 3)
        {
            cout<<"You matched 3 and broke even"<<endl;
        }
        else if( total == 4)
        {
            win_amt = bet_amt*2;
            total_amt = total_amt + (win_amt - bet_amt);
            cout<<"Congrats! you matched 4!!"<<endl;
            cout<<"You now have $"<<total_amt<<"dollars!"<<endl;
        }
        else
        {
            win_amt = bet_amt*5;
            total_amt = total_amt + (win_amt - bet_amt);
            cout<<"WINNER WINNER YOU MATCHED 5!!"<<endl;
            cout<<"You now have $"<<total_amt<<"dollars!"<<endl;
        }
     // end nested if-else

}  // end for loop

} // end main

Answer 1

没有必要在函数开始时“预先声明”所有变量。

如果您希望变量“重置”，请在循环内将变量声明移动到您使用它们的位置：

for (int i=0;i<play_amt;i++)
{
    int total = 0; // A new variable 'total', that starts at 0 each time through the loop.

Answer 2

你应该养成委派任务到函数的习惯。您遇到total问题，因为您的main()功能太长，很难跟踪该变量发生的情况。如果您的for循环如下所示，那么您将遇到更少的麻烦：

for (i=0;i<play_amt;i++)
{
  read_choices(user_choice);
  choose_random(com_coice);
  display_choice(com_choice);

  total = count_matches();
  cout<<"User matched "<<total<<"times"<<endl;

  total_amt += evaluate_scenario(total, bet_amt);
}  // end for loop

c ++需要刷新变量

2 个答案: