C ++为什么我在这个派生类中遇到错误

时间:2013-12-15 19:45:38

标签: c++

对于我的tic tac toe游戏,我有一个基类Player和两个派生类HumanPlayer和AIPlayer。当我第一次创建类时,我在一个.h文件中编写了HumanPlayer类。现在,由于我已经分离了实现和头文件,我在Dev C ++中遇到了一个错误:“'{'token'之前的预期类名。

我似乎无法找到问题。

这是HumanPlayer类和基类Player。也许有人可以发现问题。 Player.h

#pragma once // include guard
#include "Board.h"

class Player
{
    public:
        virtual void makeAMove(Board &myBoard) = 0; // will accept pointer to board object as param
};

HumanPlayer.h

#pragma once // include guard
#include "Board.h"

class HumanPlayer: public Player
{
    public:
        HumanPlayer(char token);
        virtual void makeAMove(Board &myBoard); 

    private:
        char token;
        int askForRow();    
        int askForColumn();
};

HumanPlayer.cpp

#include "HumanPlayer.h"
#include <cstdlib> // atoi

HumanPlayer::HumanPlayer(char token)
{
    this->token = token;
}

void HumanPlayer::makeAMove(Board &myBoard) 
{
    bool done = false;
    do 
    {
        int row = askForRow();

        int column = askForColumn();

        if (myBoard.getCell(row, column) == ' ')
        { 
            myBoard.setCell(row, column, token);
            done = true;
        }
        else
            std::cout << "This cell is already occupied. Try a different cell" << std::endl;
    }
    while (!done);
}

int HumanPlayer::askForRow()
{
    while(true)
    {
        std::cout << "Enter a row (0, 1, 2) for player " << token << ": ";
        std::string row_s; 
        std::getline(std::cin, row_s);
        if (row_s == "0" || row_s == "1" || row_s == "2")
        {
            return atoi(row_s.c_str());
        }
        else
        {
            std::cout << "\nInvalid input\n";
        }
    }
}

int HumanPlayer::askForColumn()
{
    while(true)
    {
        std::cout << "Enter a column (0, 1, 2) for player " << token << ": ";
        std::string column_s; 
        std::getline(std::cin, column_s);
        if (column_s == "0" || column_s == "1" || column_s == "2")
        {
            return atoi(column_s.c_str());
        }
        else
        {
            std::cout << "\nInvalid input\n";
        }
    }
}

1 个答案:

答案 0 :(得分:2)

我没有看到标题HumanPlayer.h包含类Player的定义。