Question

我无法弄清楚我在使用Python 2.7编写的代码时遇到的问题。我正在将引用转换为int，但我不断收到类型异常bad operand type for unary +: 'str'。有人可以帮忙吗？

import urllib2
import time
import datetime

stocksToPull = 'EBAY', 'AAPL'


def pullData(stock):
    try:
        print 'Currently pulling', stock
        print str(datetime.datetime.fromtimestamp(time.time()).strftime('%Y-%m-%d %H:%M:%S'))
        urlToVisit = 'http://chartapi.finance.yahoo.com/instrument/1.0/' + \
            stock + '/chartdata;type=quote;range=3y/csv'
        saveFileLine = stock + '.txt'

        try:
            readExistingData = open(saveFileLine, 'r').read()
            splitExisting = readExistingData.split('\n')
            mostRecentLine = splitExisting[-2]
            lastUnix = mostRecentLine.split(',')[0]
        except Exception, e:
            print str(e)
            time.sleep(1)
            lastUnix = 0

        saveFile = open(saveFileLine, 'a')
        sourceCode = urllib2.urlopen(urlToVisit).read()
        splitSource = sourceCode.split('\n')

        for eachLine in splitSource:
            if 'values' not in eachLine:
                splitLine = eachLine.split(',')
                if len(splitLine) == 6:
                    if int(splitLine[0]) > int(lastUnix):
                        lineToWrite = eachLine + '\n'
                        saveFile.write(lineToWrite)
        saveFile.close()

        print 'Pulled', + stock
        print 'Sleeping....'
        print str(datetime.datetime.fromtimestamp(time.time()).strftime('%Y-%m-%d %H:%M:%S'))
        time.sleep(120)

    except Exception, e:
        print 'main loop', str(e)


for eachStock in stocksToPull:
    pullData(eachStock)

我到达bad operand type for unary +: 'str'时遇到操作数异常if int(splitLine[0]) > int(lastUnix):，即使被比较的两个值在测试时打印为整数。任何人都可以给我一些反馈吗？谢谢！

这是异常响应：

Currently pulling EBAY
2013-12-21 11:32:40
Pulled main loop bad operand type for unary +: 'str'
Currently pulling AAPL
2013-12-21 11:32:41
Pulled main loop bad operand type for unary +: 'str'`

Answer 1

你说if int(splitLine[0]) > int(lastUnix):造成了麻烦，但实际上并没有显示任何暗示这一点的内容。我认为这一行是问题所在：

print 'Pulled', + stock

你知道为什么这一行会导致错误信息吗？你想要

>>> stock = "AAAA"
>>> print 'Pulled', stock
Pulled AAAA

或

>>> print 'Pulled ' + stock
Pulled AAAA

不

>>> print 'Pulled', + stock
PulledTraceback (most recent call last):
  File "<ipython-input-5-7c26bb268609>", line 1, in <module>
    print 'Pulled', + stock
TypeError: bad operand type for unary +: 'str'

你要求Python将+符号应用于像+23这样的字符串，使其成为正23，并且她反对。

Answer 2

该代码适合我。（在添加缺少的except子句/ import语句后）

您是否将\放入原始代码中？

urlToVisit = 'http://chartapi.finance.yahoo.com/instrument/1.0/' \
              + stock + '/chartdata;type=quote;range=5d/csv'

如果省略它，可能是异常的原因：

>>> stock = 'GOOG'
>>> urlToVisit = 'http://chartapi.finance.yahoo.com/instrument/1.0/'
>>> + stock + '/chartdata;type=quote;range=5d/csv'
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: bad operand type for unary +: 'str'

BTW，string(e)应为str(e)。

一元+的错误操作数类型：'str'

2 个答案: