Question

我知道如何使用awk或sed在文件中找到长行：

$ awk 'length<=5' foo.txt

只会打印长度为＆lt; = 5的行。

sed -i '/^.\{5,\}$/d' FILE

将删除超过5个字符的所有行。

但是如何通过插入延续字符（在我的情况下为'＆amp;'）和换行符来找到长行然后分解它们？

背景

我有一些自动生成的fortran代码。不幸的是，有些行超过了132个字符的限制。我想找到它们并自动分解它们。例如，这：

 this is a might long line and should be broken up by inserting the continuation charater '&' and newline.

应该成为这个：

 this is a might long line and should be broken &
 up by inserting the continuation charater '&' a&
 nd newline.

Answer 1

sed的一种方式：

$ sed -r 's/.{47}/&\&\n/g' file
this is a might long line and should be broken &
up by inserting the continuation charater '&' a&
nd newline.

Answer 2

您可以尝试：

awk '
BEGIN { p=47 }
{
    while(length()> p) {
        print substr($0,1,p) "&"
        $0=substr($0,p+1)
    }
    print
}' file

Answer 3

此解决方案不需要sed或awk。这很有趣。

tr '\n' '\r' < file | fold -w 47 | tr '\n\r' '&\n' | fold -w 48

这就是你得到的：

this is a might long line and should be broken &
up by inserting the continuation charater '&' a&
nd newline.
But this line should stay intact
Of course, this is not a right way to do it and&
 you should stick with awk or sed solution
But look! This is so tricky and fun!

Answer 4

与sudo_O的代码类似，但是在awk

中执行

 awk '{gsub(/.{47}/,"&\\&\n")}1' file

Bash：如何通过插入延续字符和换行来查找和分解长行？

4 个答案: