我想将这个文本文件分成3个文本文件,每个段落都是一个文本文件。(我的Os是ubuntu12.04)
输入 2008 2 2 1120 31.2 L 34.031 48.515 16.7 INS 5 0.3 4.0LINS 1 GAP = 145 0.67 4.1 2.9 6.6 0.2283E-01 -0.1718E + 00 0.1289E + 02E 行动:UPD 08-12-28 13:25 OP:moh状态:ID:20080202112031我 2008-02-02-1120-39S.IN ____ 006 6 STAT SP IPHASW D HRMM SECON CODA AMPLIT PERI AZIMU VELO AIN AR TRES W DIS CAZ7 SNGE BZ EPg 1120 57.69 91 0.0210 159 318 SNGE BZ AML 1121 24.50 2880.9 0.55 159 318 SHGR BZ EPN5 1121 5.17 52 -0.0510 215 173 GHVR BZ EPn 1121 10.84 52 0.3610 256 78 GHVR BZ ESg 1121 43.50 91 -0.0210 256 78 CHTH BZ EPn 1121 18.26 52 0.1210 317 48 CHTH BZ AML 1122 8.01 494.0 0.68 317 48 DAMV BZ EPn 1121 23.36 52 -0.49 9 362 60 DAMV BZ AML 1122 7.03 382.0 0.48 362 60
2008 211 1403 46.2 L 27.659 55.544 14.1 INS 4 0.1 4.0LINS 1 GAP = 171 0.38 1.7 1.2 3.3 -0.8271E-01 -0.3724E-01 0.4284E + 00E 2008-02-11-1403-37S.INSN__048 6 行动:新08-12-28 13:25 OP:moh状态:ID:20080211140346我 STAT SP IPHASW D HRMM SECON CODA AMPLIT PERI AZIMU VELO AIN AR TRES W DIS CAZ7 BNDS BZ EPg 14 3 58.14 90 -0.0710 68.3 115 BNDS BN AML 14 4 26.39 8461.0 0.52 68.3 115 GHIR BZ EPn 14 4 26.40 52 0.0310 261 286 GHIR BN ESg 14 4 59.85 90 -0.0110 261 286 GHIR BN AML 14 5 25.22 1122.4 0.56 261 286 GHIR BE AML 14 5 43.83 769.3 0.64 261 286 KRBR BZ EPn 14 4 29.25 52 -0.1110 284 24 KRBR BN ESg 14 5 6.28 90 0.0010 284 24 KRBR BN AML 14 5 18.89 552.4 0.64 284 24 KRBR BE AML 14 5 19.22 574.0 0.60 284 24 ZHSF BZ EPn 14 5 3.24 52 0.25 8 555 66
2008 213 2055 31.5 L 31.713 51.180 14.1 INS 9 0.5 4.2LINS 1 GAP = 127 1.21 4.6 6.5 9.6 0.7570E + 01 -0.1161E + 02 0.9944E + 01E 行动:UPD 08-12-28 13:25 OP:moh状态:ID:20080213205531我 2008-02-13-2054-59S.NSN ___ 048 6 STAT SP IPHASW D HRMM SECON CODA AMPLIT PERI AZIMU VELO AIN AR TRES W DIS CAZ7 NASN BZ EPg 2056 3.15 90 -0.6410 195 51 SHGR BZ EPg 2056 8.57 90 -0.3810 229 282 SHGR BN AML 2056 49.27 2371.2 0.77 229 282 SHGR BE AML 2056 51.00 2484.4 0.77 229 282 GHVR BZ EPn 2056 18.39 52 1.0110 307 1 GHVR BE AML 2057 11.42 734.2 0.85 307 1 ASAO BZ EPn 2056 20.35 52 -0.36 9 332 341 ASAO BE ESg 2057 5.23 90 0.27 9 332 341 ASAO BN AML 2057 15.86 723.3 0.64 332 341 GHIR BZ EPn 2056 31.68 52 0.48 9 418 155 GHIR BN AML 2057 51.30 259.1 0.79 418 155 DAMV BZ EPn 2056 33.90 52 -0.27 9 441 9 DAMV BN AML 2057 43.30 237.4 0.65 441 9 THKV BZ EPn 2056 37.71 52 0.33 8 467 357 THKV BE AML 2057 51.62 205.7 0.72 467 357 ZNJK BZ EPn 2056 53.12 52 -0.35 7 596 338 BNDS BZ EPn 2057 3.72 52 -0.06 7 680 133
output1.txt 2008 2 2 1120 31.2 L 34.031 48.515 16.7 INS 5 0.3 4.0LINS 1 GAP = 145 0.67 4.1 2.9 6.6 0.2283E-01 -0.1718E + 00 0.1289E + 02E 行动:UPD 08-12-28 13:25 OP:moh状态:ID:20080202112031我 2008-02-02-1120-39S.IN ____ 006 6 STAT SP IPHASW D HRMM SECON CODA AMPLIT PERI AZIMU VELO AIN AR TRES W DIS CAZ7 SNGE BZ EPg 1120 57.69 91 0.0210 159 318 SNGE BZ AML 1121 24.50 2880.9 0.55 159 318 SHGR BZ EPN5 1121 5.17 52 -0.0510 215 173 GHVR BZ EPn 1121 10.84 52 0.3610 256 78 GHVR BZ ESg 1121 43.50 91 -0.0210 256 78 CHTH BZ EPn 1121 18.26 52 0.1210 317 48 CHTH BZ AML 1122 8.01 494.0 0.68 317 48 DAMV BZ EPn 1121 23.36 52 -0.49 9 362 60 DAMV BZ AML 1122 7.03 382.0 0.48 362 60
output2.txt 2008 211 1403 46.2 L 27.659 55.544 14.1 INS 4 0.1 4.0LINS 1 GAP = 171 0.38 1.7 1.2 3.3 -0.8271E-01 -0.3724E-01 0.4284E + 00E 2008-02-11-1403-37S.INSN__048 6 行动:新08-12-28 13:25 OP:moh状态:ID:20080211140346我 STAT SP IPHASW D HRMM SECON CODA AMPLIT PERI AZIMU VELO AIN AR TRES W DIS CAZ7 BNDS BZ EPg 14 3 58.14 90 -0.0710 68.3 115 BNDS BN AML 14 4 26.39 8461.0 0.52 68.3 115 GHIR BZ EPn 14 4 26.40 52 0.0310 261 286 GHIR BN ESg 14 4 59.85 90 -0.0110 261 286 GHIR BN AML 14 5 25.22 1122.4 0.56 261 286 GHIR BE AML 14 5 43.83 769.3 0.64 261 286 KRBR BZ EPn 14 4 29.25 52 -0.1110 284 24 KRBR BN ESg 14 5 6.28 90 0.0010 284 24 KRBR BN AML 14 5 18.89 552.4 0.64 284 24 KRBR BE AML 14 5 19.22 574.0 0.60 284 24 ZHSF BZ EPn 14 5 3.24 52 0.25 8 555 66
output3.txt 2008 213 2055 31.5 L 31.713 51.180 14.1 INS 9 0.5 4.2LINS 1 GAP = 127 1.21 4.6 6.5 9.6 0.7570E + 01 -0.1161E + 02 0.9944E + 01E 行动:UPD 08-12-28 13:25 OP:moh状态:ID:20080213205531我 2008-02-13-2054-59S.NSN ___ 048 6 STAT SP IPHASW D HRMM SECON CODA AMPLIT PERI AZIMU VELO AIN AR TRES W DIS CAZ7 NASN BZ EPg 2056 3.15 90 -0.6410 195 51 SHGR BZ EPg 2056 8.57 90 -0.3810 229 282 SHGR BN AML 2056 49.27 2371.2 0.77 229 282 SHGR BE AML 2056 51.00 2484.4 0.77 229 282 GHVR BZ EPn 2056 18.39 52 1.0110 307 1 GHVR BE AML 2057 11.42 734.2 0.85 307 1 ASAO BZ EPn 2056 20.35 52 -0.36 9 332 341 ASAO BE ESg 2057 5.23 90 0.27 9 332 341 ASAO BN AML 2057 15.86 723.3 0.64 332 341 GHIR BZ EPn 2056 31.68 52 0.48 9 418 155 GHIR BN AML 2057 51.30 259.1 0.79 418 155 DAMV BZ EPn 2056 33.90 52 -0.27 9 441 9 DAMV BN AML 2057 43.30 237.4 0.65 441 9 THKV BZ EPn 2056 37.71 52 0.33 8 467 357 THKV BE AML 2057 51.62 205.7 0.72 467 357 ZNJK BZ EPn 2056 53.12 52 -0.35 7 596 338 BNDS BZ EPn 2057 3.72 52 -0.06 7 680 133
答案 0 :(得分:0)
我给你一个想法,只有一种方法:逐行迭代你的文件 保存在缓冲区中的所有行,而行!=“”或行!='\ n':在这种情况下,将缓冲区保存在不同的文件中。
buffer=""
id=0
cat test | \
while read row; do
#check row value, save in buffer
.....
cat buffer > fileName_${id}.txt
id=$((id+1))
done