我正在开发一个发送和接收短信的应用。发送是可以的,但是在应用程序运行时收到短信接收也可以,但是当我关闭应用程序时,我的BroadcastReceiver的onReceive方法没有执行,实际上我正在研究android 4而且我从大学那里听到了它可能是Android的版本,这意味着Android 4不允许应用程序接收短信时,他们没有向用户显示。是不是?
这里的代码是好的(我想是的)
public class SMSReceiver extends BroadcastReceiver {
private static final String SMS_RECEIVED = "android.provider.Telephony.SMS_RECEIVED";
private static final String ACTIVITY_SERVICE = "activity";
@Override
public void onReceive(Context context, Intent intent) {
// something
}
}
这里是与清单相关的内容
<uses-permission android:name="android.permission.WAKE_LOCK" />
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION" />
<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION" />
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" />
<uses-permission android:name="android.permission.ACCESS_WIFI_STATE" />
<uses-permission android:name="android.permission.READ_PHONE_STATE" />
<uses-permission android:name="android.permission.SEND_SMS" />
<uses-permission android:name="android.permission.READ_CONTACTS" />
<uses-permission android:name="android.permission.RECEIVE_SMS" />
<uses-sdk
android:minSdkVersion="8"
android:targetSdkVersion="15" />
<receiver
android:name="com.ssol.SMSReceiver"
android:permission="android.permission.BROADCAST_SMS" >
<intent-filter android:priority="2147483647" >
<action android:name="android.intent.action.PHONE_STATE" />
<action android:name="android.provider.Telephony.SMS_RECEIVED" />
</intent-filter>
</receiver>
答案 0 :(得分:1)
你可以收到短信及其信息。
我使用以下方式收到:
import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
import android.os.Bundle;
import android.telephony.SmsMessage;
import android.widget.Toast;
public class SMSReceiver extends BroadcastReceiver
{
public void onReceive(Context context, Intent intent)
{
Bundle myBundle = intent.getExtras();
SmsMessage [] messages = null;
String strMessage = "";
if (myBundle != null)
{
//get message in pdus format(protocol discription unit)
Object [] pdus = (Object[]) myBundle.get("pdus");
//create an array of messages
messages = new SmsMessage[pdus.length];
for (int i = 0; i < messages.length; i++)
{
//Create an SmsMessage from a raw PDU.
messages[i] = SmsMessage.createFromPdu((byte[]) pdus[i]);
//get the originating address (sender) of this SMS message in String form or null if unavailable
strMessage += "SMS From: " + messages[i].getOriginatingAddress();
strMessage += " : ";
//get the message body as a String, if it exists and is text based.
strMessage += messages[i].getMessageBody();
strMessage += "\n";
}
//show message in a Toast
Toast.makeText(context, strMessage, Toast.LENGTH_SHORT).show();
}
}
}
要获得更多帮助,您可以看到有关短信发送和receiving。
的帖子答案 1 :(得分:1)
尝试将清单中的接收器更改为
<receiver
android:name="com.ssol.SMSReceiver android:exported="true""
android:permission="android.permission.BROADCAST_SMS" >
<intent-filter android:priority="1000" >
<action android:name="android.intent.action.PHONE_STATE" />
<action android:name="android.provider.Telephony.SMS_RECEIVED" />
</intent-filter>
</receiver>
android:exported表示SmsReceiver类不仅必须从应用程序接收事件,还要从整个Android系统接收事件。
android:priority表示短信接收的优先级。 1000是默认值,似乎是最佳使用值。
希望这有帮助:)
答案 2 :(得分:0)
尝试使用此代码:
import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
import android.os.Bundle;
import android.telephony.SmsMessage;
public class ReadSMS extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
Bundle myBundle = intent.getExtras();
SmsMessage[] messages = null;
if (myBundle != null) {
Object[] pdus = (Object[]) myBundle.get("pdus");
messages = new SmsMessage[pdus.length];
String SMS = "";
for (int i = 0; i < messages.length; i++) {
messages[i] = SmsMessage.createFromPdu((byte[]) pdus[i]);
SMS = messages[i].getMessageBody();4
//SMS is the text content
}
}
}
}
适合我:)