Question

我正在使用Spring 4 websockets and stomp进行实验，我很难弄清楚如何在使用@MessageMapping注释的消息处理方法中获取/设置当前用户和其他会话属性。

The documentation说消息处理方法可以将Principal作为参数，我发现Spring通过在本机套接字会话上调用getUserPrincipal()来检索主体，然后与套接字关联session，但我没有找到任何方法来轻松自定义此行为，除了编写servlet过滤器并将原始请求包装回包装器中，返回我的cookie中找到的主体。

所以我的问题是：

如何在客户端连接时手动将主体设置为套接字会话（由于自定义cookie，我有这个信息，而且我不使用Spring安全性）？
如果无法使用1，如何在客户端连接时向套接字会话添加其他属性？
如何从消息处理方法访问套接字会话及其属性？
有没有办法在连接时访问浏览器发送的登录名和密码。它们似乎被Spring完全忽略，无法访问。

Answer 1

更新：使用Spring 4.1，可以从上面为＃1的握手设置用户。每the Spring documentation您可以创建一个新类，它扩展DefaultHandshakeHandler并覆盖determineUser方法。此外，您还可以创建一个安全过滤器，如果您有令牌，也可以设置主体。我自己实现了第二个，我在下面提供了一些示例代码。

对于＃2和＃3，我认为它仍然不可能。对于＃4 Spring，故意忽略这些the documentation here。

DefaultHandshakeHandler SUBCLASS的示例代码：

@Configuration
@EnableWebSocketMessageBroker
public class ApplicationWebSocketConfiguration extends AbstractWebSocketMessageBrokerConfigurer {

    public class MyHandshakeHandler extends DefaultHandshakeHandler {

        @Override
        protected Principal determineUser(ServerHttpRequest request, WebSocketHandler wsHandler, 
                                          Map<String, Object> attributes) {
            // add your own code to determine the user
            return null;
        }
    }

    @Override
    public void registerStompEndpoints(StompEndpointRegistry registry) {

        registry.addEndpoint("/myEndPoint").setHandshakeHandler(new MyHandshakeHandler());

    }
}

安全过滤器的示例代码：

public class ApplicationSecurityTokenFilter extends GenericFilterBean {

    private final static String AUTHENTICATION_PARAMETER = "authentication";

    @Override
    public void doFilter(ServletRequest servletRequest, ServletResponse servletResponse, FilterChain filterChain) throws IOException, ServletException {
        if (servletRequest instanceof HttpServletRequest) {
            // check to see if already authenticated before trying again
            Authentication existingAuth = SecurityContextHolder.getContext().getAuthentication();
            if ((existingAuth == null) || !existingAuth.isAuthenticated()) {
                HttpServletRequest request = (HttpServletRequest)servletRequest;
                UsernamePasswordAuthenticationToken token = extractToken(request);
                // dump token into security context (for authentication-provider to pick up)
                if (token != null) {  // if it exists
                    SecurityContextHolder.getContext().setAuthentication(token);
                }
            }
        }
        filterChain.doFilter(servletRequest,servletResponse);
    }

    private UsernamePasswordAuthenticationToken extractToken( HttpServletRequest request ) {
        UsernamePasswordAuthenticationToken authenticationToken = null;
        // do what you need to extract the information for a token
        // in this example we assume a query string that has an authenticate
        // parameter with a "user:password" string.  A new UsernamePasswordAuthenticationToken
        // is created and then normal authentication happens using this info.
        // This is just a sample and I am sure there are more secure ways to do this.
        if (request.getQueryString() != null) {
            String[] pairs = request.getQueryString().split("&");
            for (String pair : pairs) {
                String[] pairTokens = pair.split("=");
                if (pairTokens.length == 2) {
                    if (AUTHENTICATION_PARAMETER.equals(pairTokens[0])) {
                        String[] tokens = pairTokens[1].split(":");
                        if (tokens.length == 2) {
                            log.debug("Using credentials: " + pairTokens[1]);
                            authenticationToken = new UsernamePasswordAuthenticationToken(tokens[0], tokens[1]);
                        }
                    }
                }
            }
        }
        return authenticationToken;
    }
}

// set up your web security for the area in question
@Configuration
public class SubscriptionWebSecurityConfigurationAdapter extends WebSecurityConfigurerAdapter {

    protected void configure(HttpSecurity http) throws Exception {
        http
                .requestMatchers().antMatchers("/myEndPoint**","/myEndPoint/**").and()
                .addFilterBefore(new ApplicationSecurityTokenFilter(), UsernamePasswordAuthenticationFilter.class)
                .authorizeRequests()
                .anyRequest().authenticated()
                .and()
                .httpBasic()  // leave this if you want non web browser clients to connect and add an auth header
                .and()
                .csrf().disable();
    }
}

** 注意： **不要将过滤器声明为Bean。如果你这样做，它也会在通用过滤器中被拾取（至少使用Spring Boot），因此它将在每个请求中触发。

Answer 2

暂时不可能（Spring 4.0）。 Spring上已经打开（并考虑过）一个问题：https://jira.springsource.org/browse/SPR-11228

如何从Spring 4 stomp websocket方法获取/设置主体和会话属性

2 个答案: