Question

我正在尝试编写一个程序来访问网站并下载他们发布的所有歌曲。现在我无法为我下载的每首歌创建新的文件名。我最初获得所有文件名和歌曲的位置（html）。但是，当我尝试为要放入的歌曲创建新文件时，我收到错误消息：

IOError：[Errno 22]无效模式（'w'）或文件名

我尝试使用不同的模式，如“w +”，“a”和“a +”来查看这些是否可以解决问题，但到目前为止我一直收到错误消息。我也试过“％name” - 字符串，但是也没用。我的代码如下，任何帮助将不胜感激。

import urllib
import urllib2

def earmilk():
    SongList = []
    SongStrings = []
    SongNames = []
    earmilk = urllib.urlopen("http://www.earmilk.com/category/pop")
    reader = earmilk.read()
    #gets the position of the playlist
    PlaylistPos = reader.find("var newPlaylistTracks = ")
    #finds the number of songs in the playlist
    NumberSongs = reader[reader.find("var newPlaylistIds = " ): PlaylistPos].count(",") + 1
    initPos = PlaylistPos

    #goes though the playlist and records the html address and name of the song

    for song in range(0, NumberSongs):
        songPos = reader[initPos:].find("http:") + initPos
        namePos = reader[songPos:].find("name") + songPos
        namePos += reader[namePos:].find(">")
        nameEndPos = reader[namePos:].find("<") + namePos
        SongStrings.append(reader[songPos: reader[songPos:].find('"') + songPos])
        SongNames.append(reader[namePos + 1: nameEndPos])
        #initPos += len(SongStrings[song])
        initPos = nameEndPos

    for correction in range(0, NumberSongs):
        SongStrings[correction] = SongStrings[correction].replace('\\/', "/")

    #downloading songs

    #for download in range(0, NumberSongs):
    #print reader.find("So F*")
    #x= SongNames[0]
    songDL = open(SongNames[0].formant(name), "w+")
    songDL.write(urllib.urlretrieve(SongStrings[0], SongNames[0] + ".mp3"))
    songDL.close()


    print SongStrings
    for name in range(0, NumberSongs):
        print SongNames[name] + "\n"
    earmilk.close()

Answer 1

您需要使用filename = '%s' % (SongNames[0],)来构建名称但您还需要确定您的文件名是有效的 - 我不知道知道任何名为*.*的歌曲，但我不想冒这样的话：

filename = ''.join([a.isalnum() and a or '_' for a in SongNames[0]])

Python：基于字符串数组创建文件

1 个答案: