我有六张照片需要复制到一个足够大的窗口,以免它们重叠而不会留下多余的空间。我正在迈出需要我编写showOff()的步骤。我的任务说实例化EditablePicture的操作是
EditablePicture bigshowPict = new EditablePicture(??,??);
我需要一个循环,将我的数组中的图片逐个复制到EditablePicture中
bigShowPict.copyIn(??,??,this.pictArray[??]);
其中循环计算一个或两个??,??找出复制图片的位置.EditablePicture类和bigShowPict方法是预定义的,不应该被更改。到目前为止,我的所有代码都是
House.java
public class House
{
String owner;
public final static int CAPACITY = 6;
Picture[ ] pictArray = new Picture[6];
public House(String pString)
{
this.owner = pString;
}
public String toString()
{
return("The House owned by " + this.owner);
}
public void acquire( int i, Picture pRef )
{
this.pictArray[i] = pRef;
}
public void printPictures()
{
for (int i=0; i < this.pictArray.length;i++)
{
System.out.print("The Picture in position " + i + " is ");
System.out.println( this.pictArray[ i ]);
}
}
public void swap( int positionA, int positionB )
{
System.out.println("NOTHING DONE. THIS IS JUST A swap's STUB");
}
public void showOff()
{
int sum = 0;
for (int i=0; i<7;i++)
{
sum = sum + this.pictArray[i].getWidth();
int resultHeight=1000;
int resultWidth = sum;
bigShowPict.copyIn(resultWidth,resultHeight,this.pictArray[i]);
EditablePicture bigShowPict = new EditablePicture(resultWidth,resultHeight);
bigShowPict.show();
}
}
}
以及调用它们的应用 Test.java
import java.util.Scanner;
public class Test
{
public static void main(String[] a)
{
House myHouse;
myHouse = new House("Justin Chaisetseree");
Scanner sc = new Scanner(System.in);
FileChooser.pickMediaPath();
for( int i = 0; i < 6; i++)
{
myHouse.acquire(i,new Picture(FileChooser.pickAFile()));
}
myHouse.printPictures();
myHouse.showOff();
Boolean done = false;
while( ! done )
{
System.out.println("Which two do you want to swap?");
System.out.print("Type in two numbers from 0 to ");
System.out.print( 5 );
System.out.println(" or two -1s to stop.");
int userInput1 = sc.nextInt();
int userInput2 = sc.nextInt();
if( userInput1 < 0 || userInput2 < 0)
{
done = true;
}
else
{
myHouse.swap( userInput1, userInput2 );
}
}
myHouse.showOff();
}
}