Question

我正在尝试使用Google的API和PHP获取大量不同的图片。代码适用于单个图像，但是当我尝试使用FOR - LOOP 中的相同代码获取不同主题图像时，我始终只获得第一个结果：< / p>

$images = array("ironman poster", "superman returns poster", "the croods poster", "batman forever poster");

foreach ($images as $i) {
    $image = rawurlencode($i);
    $query = "https://ajax.googleapis.com/ajax/services/search/images?v=1.0&q=".$image."&imgsz=large&as_filetype=jpg";

    $json = get_url_contents($query);
    $data = json_decode($json);
    foreach ($data->responseData->results as $result) {
        $results[] = array("url" => $result->url, "alt" => $result->title);
    }

    echo $results[0]['url'];
    echo "<br />";
    echo $query;
    echo "<br />";
}

function get_url_contents($url) {
    $crl = curl_init();
    curl_setopt($crl, CURLOPT_USERAGENT, 'Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; .NET CLR 1.1.4322)');
    curl_setopt($crl, CURLOPT_URL, $url);
    curl_setopt($crl, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($crl, CURLOPT_CONNECTTIMEOUT, 5);

    $ret = curl_exec($crl);
    curl_close($crl);
    return $ret;
}

Answer 1

您需要在循环迭代之前定义$results数组。我不确定为什么它不起作用，也许其他人可以详细说明？

工作解决方案：

$ images = array（“铁人海报”，“超人回归海报”，“croods海报”，“蝙蝠侠永远海报”）;

foreach ($images as $i) {
    $image = rawurlencode($i);
    $query = "https://ajax.googleapis.com/ajax/services/search/images?v=1.0&q=".$image."&imgsz=large&as_filetype=jpg";

    $json = get_url_contents($query);
    $data = json_decode($json);
    $results = array(); //define array here!
    foreach ($data->responseData->results as $result) {
        $results[] = array("url" => $result->url, "alt" => $result->title);
    }

    echo $results[0]['url'];
    echo "<br />";
    echo $query;
    echo "<br />";
}

使用Google图像检索图像API和CURL始终具有相同的链接

1 个答案: