Question

我有2列日期和年份。在该日期之下，一年中每个月都有行。为了只显示年份列的不同值，我用空值替换了重复项，但是当我在报表中调用该列时，它只在每年之间放置了空白行。此表严格用于创建可用于过滤报表的参数列表。

现在我的表看起来像这样：

Date        Year
-----------------
1/2013      2013
2/2013      2013
3/2013      2013
.
.
.
12/2013     2013
1/2014      2014
2/2014      2014

以下是我希望表格的样子。

Date        Year
-----------------
1/2013      2013
2/2013      2014
3/2013      2015
.             .
.             .
.             .
12/2013       .
1/2014        .
2/2014        .

以下是我正在使用的查询：

            SELECT  rmp.EcoDate as Date,
            year(rmp.EcoDate) as Year, 

            FROM      PhdRpt.ReportCaseList_542 AS rcl INNER JOIN
                      CaseCases AS cc ON rcl.CaseCaseId = cc.CaseCaseId INNER JOIN
                      PhdRpt.RptMonthlyProduction_542 AS rmp ON rcl.ReportRunCaseId = rmp.ReportRunCaseId
            GROUP BY rmp.EcoDate

最好的方法是创建2个临时表并创建一个公共字段，如行和该行的连接，还是有更简洁的方法？在年末列中，我希望只有空值来填充其余行。

提前感谢您的帮助。

Answer 1

我能够通过在自己的临时表中对年份和日期进行分组，然后使用row_number创建公共列，然后使用第一个表到第二个表进行完全外部连接来解决这个问题。这是查询：

SELECT      CAST(MONTH(rmp.EcoDate) AS Varchar(2)) + '/' + CAST(YEAR(rmp.EcoDate) AS varchar(4)) AS Date,  
            rmp.EcoDate as EcoDate,
            row_number() over ( order by rmp.ecodate) as seqnum
into #a
FROM         PhdRpt.ReportCaseList_542 AS rcl INNER JOIN
                      CaseCases AS cc ON rcl.CaseCaseId = cc.CaseCaseId INNER JOIN
                      PhdRpt.RptMonthlyProduction_542 AS rmp ON rcl.ReportRunCaseId = rmp.ReportRunCaseId
GROUP BY rmp.EcoDate

SELECT      year(rmp.EcoDate) as Year, 
            CONVERT (datetime,convert(char(8),YEAR(rmp.EcoDate) )) as EcoYear,
            row_number() over ( order by year(rmp.ecodate)) as seqnum
into #b
FROM         PhdRpt.ReportCaseList_542 AS rcl INNER JOIN
          CaseCases AS cc ON rcl.CaseCaseId = cc.CaseCaseId INNER JOIN
          PhdRpt.RptMonthlyProduction_542 AS rmp ON rcl.ReportRunCaseId = rmp.ReportRunCaseId
GROUP BY year(rmp.EcoDate)

 Select *
 From #a a
 Full Outer Join #b b on a.seqnum = b.seqnum

 drop table #a, #b

将2列与不同的行组合在一起，在SQL中没有任何共同点

1 个答案: