Question

我正在我的本地Windows 8开发机器上构建一个站点（使用wamp）。我有一个PHP脚本，假设从我服务器上的目录中获取图像文件并将它们上传到基于WordPress的网站。当我在目录中有一个文件时，一切正常。当我修改代码以从目录上传多个文件时，只上传了一个图片，我收到错误消息：file_get_content(/path/to/directory/): failed ot open stream. Permission denied in /path/to/script/这是我收到的错误的图片http://i.imgur.com/rRvxKa0.jpg

以下代码适用于目录中的一个文件：

    global $post;

    $rpcurl = get_bloginfo('url') . "/xmlrpc.php";

    $username = 'admin';
    $password = 'admin';
    $blogid = $post->ID; //Post ID

    $post_idn = get_post_meta($post->ID, 'VIN', true);

    $post_dir = dirname( get_template_directory() ) . "/" . $post_idn;

    $file = file_get_contents( $post_dir . "/file.jpg");

    $filetype = "image/jpeg";

    $filename = "remote_filename.jpg";

    xmlrpc_set_type($file,'base64'); // <-- required!
    $params = array($blogid,$username,$password,
                array('name'=>$filename,'type'=>$filetype,'bits'=>$file,'overwrite'=>false));
    $request = xmlrpc_encode_request('wp.uploadFile',$params);

    function go($request,$rpcurl){
        $ch = curl_init();
        curl_setopt($ch,CURLOPT_POST,1);
        curl_setopt($ch,CURLOPT_URL,$rpcurl);
        curl_setopt($ch,CURLOPT_POSTFIELDS,$request );
        curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
        $result = curl_exec($ch);
    }

    $result = go($request,$rpcurl);
    print_r($result);

以下是上传多张图片的代码。

    $rpcurl = get_bloginfo('url') . "/xmlrpc.php";

    echo $rpcurl; 

    $username = 'admin';
    $password = 'admin';
    $blogid = $post->ID; //Post ID

    echo $blogid;

    $post_idn = get_post_meta($post->ID, 'VIN', true);

    echo "<h1>" . $post_idn ."</h1>";

    $post_dir = dirname( get_template_directory() ) . "/" . $post_idn;

    $fileslist = scandir($post_dir);

    foreach ($fileslist as $file) {

        $file = file_get_contents( $post_dir . "/" . $file);

        $filetype = "image/jpeg";

        $filename = "remote_filename.jpg";

        xmlrpc_set_type($file,'base64'); // <-- required!
        $params = array($blogid,$username,$password,
                    array('name'=>$filename,'type'=>$filetype,'bits'=>$file,'overwrite'=>false));
        $request = xmlrpc_encode_request('wp.uploadFile',$params);
    }

        function go($request,$rpcurl){
            $ch = curl_init();
            curl_setopt($ch,CURLOPT_POST,1);
            curl_setopt($ch,CURLOPT_URL,$rpcurl);
            curl_setopt($ch,CURLOPT_POSTFIELDS,$request );
            curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
            $result = curl_exec($ch);
        }

        $result = go($request,$rpcurl);
        print_r($result);

Answer 1

scandir will return . and .., along with all real files and subdirectories。你需要过滤掉那些：

foreach ($fileslist as $file) {
    if( $file === '.' || $file === '..' ) {
        continue;
    }

    $file = file_get_contents( $post_dir . "/" . $file);

    $filetype = "image/jpeg";

    $filename = "remote_filename.jpg";

    xmlrpc_set_type($file,'base64'); // <-- required!
    $params = array($blogid,$username,$password,
                array('name'=>$filename,'type'=>$filetype,'bits'=>$file,'overwrite'=>false));
    $request = xmlrpc_encode_request('wp.uploadFile',$params);
}

此处的提示是错误消息：file_get_contents(/path/to/directory/): failed to open stream. Permission denied in /path/to/script/如果$file是真实文件，您会看到/path/to/directory/somefile.extension，而不只是/path/to/directory/。

此外，您使用以下行为每个上传的文件指定相同的文件名：$filename = "remote_filename.jpg";因此，无论上传了多少文件，最后只留下一个（第一个，因为{{ 1}}）。

PHP脚本返回“file_get_contents

1 个答案: