Question

我有很多像这样的字符串模式的例子，但我想展示一些例子。

from:   [name:  Illianney Amada
id:     674176087]
from:   [name:  Natalia Morel-Gibbs
id:     100003799207624]
from:   [name:  Jules Kaneyge Pand
id:     100000110811550]

而且，我想说明这样的参数类型:(观看字符串和 SequenceOfNumber ）

from:   [name:  String
id:     SequenceOfNumber]

但实际上，它是从这个

表示的

from:\t[name:\tString\nid:\tSequenceofNumber]

所以，我想用替换“String”和“id：”之间的“\ n” >“，\ t”或制表符。结果应该是这样的

from:\t[name:\tString,\tid:\tSequenceofNumber]\n
from:\t[name:\tString,\tid:\tSequenceofNumber]\n
from:\t[name:\tString,\tid:\tSequenceofNumber]\n

或以其他方式这样

from:   [name:  String,    id:     SequenceOfNumber]
from:   [name:  String,    id:     SequenceOfNumber]
from:   [name:  String,    id:     SequenceOfNumber]

注意：我使用Python模块 re

实现正则表达式替换

Answer 1

<强>更新

import re
fixed = re.sub(r"(\[name:.*?)\n", r"\1,\t", originalString, re.M)

结果：

from:   [name:  Illianney Amada,       id:     674176087]
from:   [name:  Natalia Morel-Gibbs,   id:     100003799207624]
from:   [name:  Jules Kaneyge Pand,    id:     100000110811550]

工作示例：http://regex101.com/r/wN7aT0

<强>旧

如果你只有那个\n，你可以这样做：

originalString = "from:\t[name:\tString\nid:\tSequenceofNumber]"
fixedString = ",\t".join(originalString.split("\n"))

这会将\n上的字符串拆分并与,\t一起重新加入，从而产生：

from:\t[name:\tString,\tid:\tSequenceofNumber]

原始示例中的

警告：，您实际上并未在变量中设置字符串。你是否可以从文本文件中打开它？如果是这样，那会大大改变答案，因为你可能一次循环一行。

Answer 2

如果只替换模式中的'\ n'，那么就像这样：

import re

data = """from:   [name:  Jules Kaneyge Pand
id:     100000110811550]
from:   [name:  abcd
id:     100000110811550]
           """

print ',\tid:'.join(re.split("[^\]]\s*\n\s*id:", data))

你会得到：

from:   [name:  Jules Kaneyge Pan,  id:     100000110811550]
from:   [name:  abc,    id:     100000110811550]

正则表达式匹配字符串模式中的某些字符

2 个答案: