我是python-fu的新手,(我的第二天),所以我的问题似乎很天真:我想从“r400r.png”中选择一个矩形部分,将其旋转90度,然后保存我的选择“r400ra.png”。
到目前为止,我尝试了以下几点:
for fv in range(400,401):
fn='r%sr.png' % fv
img=pdb.gimp_file_load('/path/'+fn,fn)
drw=pdb.gimp_image_get_active_layer(img)
img1=pdb.gimp_image_new(1024,1568,0)
lyr=pdb.gimp_layer_new(img1,1024,1568,0,'ly1',0,0)
pdb.gimp_rect_select(img,10,200,1422,1024,2,0,0)
drw=pdb.gimp_rotate(drw,0,1.570796327)
pdb.script_fu_selection_to_image(img1,drw)
f0=fn[:5]+'a'+fn[5:]
pdb.gimp_file_save(drw,'/path/'+f0,f0)
“lyr”层就在那里,因为我的理解是它是必须的,虽然我不清楚为什么。 “for”循环最终应该批量处理一堆文件;对于测试,它仅限于一个文件。我在尝试执行“script_fu_selection_to_image”时遇到错误。
你能指出我,朝着正确的方向吗?
谢谢, SxN
答案 0 :(得分:4)
PDB要求这样做的顺序更好:
# import your image:
img=pdb.gimp_file_load('/path/'+fn,fn)
#make the selection
pdb.gimp_rect_select(img,10,200,1422,1024,2,0,0)
# copy
pdb.gimp_edit_copy(img.layers[0])
# (no need to "get_active_layer" - if
# your image is a flat PNG or JPG, it only has one layer,
# which is accessible as img.layers[0])
# create a new image from the copied area:
new_img = pdb.gimp_paste_as_new()
#rotate the newly created image:
pdb.gimp_image_rotate(new_img, ...)
#export the resulting image:
pdb.gimp_file_save(new_img, ...)
#delete the loaded image and the created image:
# (as the objects being destroyed on the Python side
# do not erase then from the GIMP app, where they
# stay consuming memory)
pdb.gimp_image_delete(new_img)
pdb.gimp_image_delete(img)