我正在尝试将类中的数据插入到db
中这里是我的模型类
package models;
import java.util.*;
import javax.persistence.*;
import javax.persistence.Entity;
import javax.validation.*;
import play.data.validation.Constraints;
import play.data.validation.Constraints.*;
import play.api.db.*;
import play.db.jpa.*;
import javax.persistence.EntityManager;
@Entity
public class MedicalIncident {
@Id
@GeneratedValue(strategy=GenerationType.AUTO)
public int id;
@Constraints.Required
public String month;
@Constraints.Required
public String place;
@Constraints.Required
public String unit;
@Constraints.Required
public String incident_type;
@Constraints.Required
public int age;
/**
* Insert this new incident submission.
*/
public void toDataBase() {
// persist object - add to entity manager
JPA.em().merge(this);
JPA.em().persist(this);
}
}
.merge方法给我错误：
[info] play - Application started (Dev)
[error] o.h.e.j.s.SqlExceptionHelper - Kolumna "MEDICALINC0_._EBEAN_INTERCEPT" nie istnieje
Column "MEDICALINC0_._EBEAN_INTERCEPT" not found; SQL statement:
select medicalinc0_.id as id1_0_0_, medicalinc0_._ebean_intercept as _ebean_i2_0_0_, medicalinc0_.age as age3_0_0_, medicalinc0_.incident_type as incident4_0_0_, medicalinc0_.month as month5_0_0_, medicalinc0_.place as place6_0_0_, medicalinc0_.unit as unit7_0_0_ from MedicalIncident medicalinc0_ where medicalinc0_.id=? [42122-172]
[error] play - Cannot invoke the action, eventually got an error: javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not prepare statement
[error] application -
! @6ghb8od3o - Internal server error, for (POST) [/incydent_medyczny/zapisz] ->
play.api.Application$$anon$1: Execution exception[[PersistenceException: org.hibernate.exception.SQLGrammarException: could not prepare statement]]
at play.api.Application$class.handleError(Application.scala:293) ~[play_2.10.jar:2.2.1]
at play.api.DefaultApplication.handleError(Application.scala:399) [play_2.10.jar:2.2.1]
at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$2$$anonfun$applyOrElse$3.apply(PlayDefaultUpstreamHandler.scala:261) [play_2.10.jar:2.2.1]
at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$2$$anonfun$applyOrElse$3.apply(PlayDefaultUpstreamHandler.scala:261) [play_2.10.jar:2.2.1]
at scala.Option.map(Option.scala:145) [scala-library.jar:na]
at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$2.applyOrElse(PlayDefaultUpstreamHandler.scala:261) [play_2.10.jar:2.2.1]
Caused by: javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not prepare statement
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1387) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1310) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1316) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.ejb.AbstractEntityManagerImpl.merge(AbstractEntityManagerImpl.java:898) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final]
at models.MedicalIncident.toDataBase(MedicalIncident.java:43) ~[na:na]
at controllers.MedicalIncidents.submit(MedicalIncidents.java:50) ~[na:na]
Caused by: org.hibernate.exception.SQLGrammarException: could not prepare statement
at org.hibernate.exception.internal.SQLStateConversionDelegate.convert(SQLStateConversionDelegate.java:123) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:49) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:125) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.engine.jdbc.internal.StatementPreparerImpl$StatementPreparationTemplate.prepareStatement(StatementPreparerImpl.java:188) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.engine.jdbc.internal.StatementPreparerImpl.prepareQueryStatement(StatementPreparerImpl.java:159) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final]
at org.hibernate.loader.Loader.prepareQueryStatement(Loader.java:1859) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final]
Caused by: org.h2.jdbc.JdbcSQLException: Kolumna "MEDICALINC0_._EBEAN_INTERCEPT" nie istnieje
Column "MEDICALINC0_._EBEAN_INTERCEPT" not found; SQL statement:
select medicalinc0_.id as id1_0_0_, medicalinc0_._ebean_intercept as _ebean_i2_0_0_, medicalinc0_.age as age3_0_0_, medicalinc0_.incident_type as incident4_0_0_, medicalinc0_.month as month5_0_0_, medicalinc0_.place as place6_0_0_, medicalinc0_.unit as unit7_0_0_ from MedicalIncident medicalinc0_ where medicalinc0_.id=? [42122-172]
at org.h2.message.DbException.getJdbcSQLException(DbException.java:329) ~[h2.jar:1.3.172]
at org.h2.message.DbException.get(DbException.java:169) ~[h2.jar:1.3.172]
at org.h2.message.DbException.get(DbException.java:146) ~[h2.jar:1.3.172]
at org.h2.expression.ExpressionColumn.optimize(ExpressionColumn.java:144) ~[h2.jar:1.3.172]
at org.h2.expression.Alias.optimize(Alias.java:52) ~[h2.jar:1.3.172]
at org.h2.command.dml.Select.prepare(Select.java:808) ~[h2.jar:1.3.172]
我只能看到它向我显示未找到列“MEDICALINC0 _._ EBEAN_INTERCEPT”这是非常明显的因为我真的在db中有该列。 我的db：
create table MedicalIncident (
id bigint not null,
month varchar(255),
place varchar(255),
unit varchar(255),
incident_type varchar(255),
age bigint,
constraint pk_MedicalIncident primary key (id))
;
或者我应该使用persist（）方法吗？
答案 0 :(得分：0)
尝试禁用EBean增强功能。在conf/application.conf文件中，注释掉ebean *的所有内容。对build.sbt文件也一样。
答案 1 :(得分：0)
我下载干净的拉链拉链。 并创建新项目。 然后我将dir应用程序配置从我的旧项目公开到新创建的。 这有助于我现在收到错误：
[PersistenceException: org.hibernate.exception.ConstraintViolationException: could not insert: [models.MedicalIncident]]
[info] play - datasource [jdbc:h2:mem:play] bound to JNDI as DefaultDS
[info] play - database [default] connected at jdbc:h2:mem:play
[info] play - Application started (Dev)
[[Ljava.lang.Object;@39fa10a8, [Ljava.lang.Object;@505ba354]
------------------------
--> - - <--
models.Unit@41fc1f20
Form(of=class models.MedicalIncident, data={id=3, incident_type=Skaleczono nożyczkami, unit=Chirurgii, age=15, month=Czerwiec, place=Place}, value=Some(models.MedicalIncident@4ae2fe41), errors={})
------------------------
------------------------
models.MedicalIncident@4ae2fe41
------------------------
[error] o.h.u.JDBCExceptionReporter - Pole nie moze byc puste "ID"
NULL not allowed for column "ID"; SQL statement:
insert into MedicalIncident (id, age, incident_type, month, place, unit) values (null, ?, ?, ?, ?, ?) [23502-172]
[error] play - Cannot invoke the action, eventually got an error: javax.persistence.PersistenceException: org.hibernate.exception.ConstraintViolationException: could not insert: [models.MedicalIncident]
[error] application -
! @6ghhj38ei - Internal server error, for (POST) [/incydent_medyczny/zapisz] ->
play.api.Application$$anon$1: Execution exception[[PersistenceException: org.hibernate.exception.ConstraintViolationException: could not insert: [models.MedicalIncident]]]
at play.api.Application$class.handleError(Application.scala:293) ~[play_2.10.jar:2.2.1]
at play.api.DefaultApplication.handleError(Application.scala:399) [play_2.10.jar:2.2.1]
at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$2$$anonfun$applyOrElse$3.apply(PlayDefaultUpstreamHandler.scala:261) [play_2.10.jar:2.2.1]
at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$2$$anonfun$applyOrElse$3.apply(PlayDefaultUpstreamHandler.scala:261) [play_2.10.jar:2.2.1]
at scala.Option.map(Option.scala:145) [scala-library.jar:na]
at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$2.applyOrElse(PlayDefaultUpstreamHandler.scala:261) [play_2.10.jar:2.2.1]
Caused by: javax.persistence.PersistenceException: org.hibernate.exception.ConstraintViolationException: could not insert: [models.MedicalIncident]
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1387) ~[hibernate-entitymanager-3.6.9.Final.jar:3.6.9.Final]
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1315) ~[hibernate-entitymanager-3.6.9.Final.jar:3.6.9.Final]
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1321) ~[hibernate-entitymanager-3.6.9.Final.jar:3.6.9.Final]
at org.hibernate.ejb.AbstractEntityManagerImpl.merge(AbstractEntityManagerImpl.java:860) ~[hibernate-entitymanager-3.6.9.Final.jar:3.6.9.Final]
at models.MedicalIncident.toDataBase(MedicalIncident.java:44) ~[na:na]
at controllers.MedicalIncidents.submit(MedicalIncidents.java:49) ~[na:na]
Caused by: org.hibernate.exception.ConstraintViolationException: could not insert: [models.MedicalIncident]
at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:96) ~[hibernate-core-3.6.9.Final.jar:3.6.9.Final]
at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:66) ~[hibernate-core-3.6.9.Final.jar:3.6.9.Final]
at org.hibernate.id.insert.AbstractReturningDelegate.performInsert(AbstractReturningDelegate.java:64) ~[hibernate-core-3.6.9.Final.jar:3.6.9.Final]
at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2345) ~[hibernate-core-3.6.9.Final.jar:3.6.9.Final]
at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2852) ~[hibernate-core-3.6.9.Final.jar:3.6.9.Final]
at org.hibernate.action.EntityIdentityInsertAction.execute(EntityIdentityInsertAction.java:71) ~[hibernate-core-3.6.9.Final.jar:3.6.9.Final]
Caused by: org.h2.jdbc.JdbcSQLException: Pole nie moze byc puste "ID"
NULL not allowed for column "ID"; SQL statement:
insert into MedicalIncident (id, age, incident_type, month, place, unit) values (null, ?, ?, ?, ?, ?) [23502-172]
at org.h2.message.DbException.getJdbcSQLException(DbException.java:329) ~[h2.jar:1.3.172]
at org.h2.message.DbException.get(DbException.java:169) ~[h2.jar:1.3.172]
at org.h2.message.DbException.get(DbException.java:146) ~[h2.jar:1.3.172]
at org.h2.table.Column.validateConvertUpdateSequence(Column.java:295) ~[h2.jar:1.3.172]
at org.h2.table.Table.validateConvertUpdateSequence(Table.java:699) ~[h2.jar:1.3.172]
at org.h2.command.dml.Insert.insertRows(Insert.java:122) ~[h2.jar:1.3.172]
在这个错误中没有出现ebean。所以我认为它已经解决了。