Question

我希望发出HTTP POST请求并使用生成的auth_token，但while循环中的print语句只打印x-dnb-user=myusername&x-dnb-pwd=mypass，而不是打印从服务器收到的响应。我无法弄清楚我哪里出错了。任何帮助，将不胜感激。此外，响应是作为字典给出的，并且令牌存在于字典的“授权”键中，在这种情况下如何检索令牌？

public void sampleAuth(){
        HttpClient client = new DefaultHttpClient();
    HttpPost post = new HttpPost("https://maxcvservices.dnb.com/rest/Authentication");
    try {
      ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
      nameValuePairs.add(new BasicNameValuePair("x-dnb-user","myemail"));
      nameValuePairs.add(new BasicNameValuePair("x-dnb-pwd","mypass"));
      post.setEntity(new UrlEncodedFormEntity(nameValuePairs));


      HttpResponse response = client.execute(post);
      BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
      String line = "";
      while ((line = rd.readLine()) != null) {
        System.out.println(line);
      }

    } catch (IOException e) {
      e.printStackTrace();
    }
    }

提前致谢！

Answer 1

我认为你可能错过了Content-type

post.setHeader("Content-type", "application/x-www-form-urlencoded");

此外，在启动rd.readLine响应之前，您应该检查响应的状态代码。服务器可能已经拒绝了您，并且没有要阅读的行！

int code = response.getStatusLine().getStatusCode();
if ( code == HttpStatus.SC_OK ) {
   // Now go fishing for the auth_token
   // Usually these things are returned as headers
} else {
   System.out.println( "You've been rejected, pal" );
}

我需要更多关于你期望的auth_token的细节，但我的猜测是它在一个名为“auth_key”的标题中，或者你可以查找它。

java简单的http auth无法正常工作

1 个答案: