Question

我想格式化一个地址。这是我的代码：

address = String.Format("{0}, {1}, {2}, {3}, {4}, {5}, {6}",
                        postalAddress.Line1,
                        postalAddress.Line2,
                        postalAddress.Line3,
                        postalAddress.Line4,
                        postalAddress.Suburb,
                        postalAddress.StateCode,
                        postalAddress.Pcode);

不幸的是，当Line2，Line3，Line4为空时，这会产生116 Knox St, , , , Watson, ACT, 2602。如何处理空值以获得116 Knox St, Watson, ACT, 2602的结果？

Answer 1

看起来这样可以更加简洁地完成您的目的。

string[] data = new[] { 
    postalAddress.Line1, 
    postalAddress.Line2, 
    postalAddress.Line3, 
    postalAddress.Line4, 
    postalAddress.Suburb, 
    postalAddress.StateCode, 
    postalAddress.Pcode 
};

string address = string.Join(", ", 
                             data.Where(e => !string.IsNullOrWhiteSpace(e));

Answer 2

你走了。这不会非常有效，但应该有效;）

StringBuilder sb = new StringBuilder();
List<string> addressParts = new List<string> { postalAddress.Line1, postalAddress.Line2, postalAddress.Line3, postalAddress.Line4, postalAddress.Suburb, postalAddress.StateCode, postalAddress.Pcode };
addressParts.ForEach(x => sb.Append(String.IsNullOrEmpty(x) ? "" : ", " + x));
string address = sb.ToString().Trim(',');

Answer 3

我推荐McAden解决方案，它很优雅，可以很好地解决您的问题。以下是关于如何使用StringBuilder的一个选项，与其他选项相比，它非常冗长。

如评论中所述，您可以使用StringBuilder和一系列if语句。 Thsi代码可以很好地清理，但是为了让你玩它并理解发生了什么，这里有一个例子：

var postalAddress = new {
    Line1 = "116 Knox St",
    Line2 = "",
    Line3 = "",
    Line4 = "",
    Suburb = "Watson",
    StateCode = "ACT",
    Pcode = "2602",
};
var builder = new StringBuilder();

builder.AppendFormat("{0}, ", postalAddress.Line1);

if(!string.IsNullOrEmpty(postalAddress.Line2))
{
    builder.AppendFormat("{0}, ", postalAddress.Line2);
}
if(!string.IsNullOrEmpty(postalAddress.Line3))
{
    builder.AppendFormat("{0}, ", postalAddress.Line3);
}
if(!string.IsNullOrEmpty(postalAddress.Line4))
{
    builder.AppendFormat("{0}, ", postalAddress.Line4);
}

builder.AppendFormat("{0}, ", postalAddress.Suburb);
builder.AppendFormat("{0}, ", postalAddress.StateCode);
builder.AppendFormat("{0}", postalAddress.Pcode);

var result = builder.ToString();

当您打印result变量时，您现在将获得以下结果：

116 Knox St, Watson, ACT, 2602

基本上你可以使用AppendFormat以格式化方式附加字符串，你可以试验并玩弄它，直到它按照你喜欢的方式运行，然后你可以将它重构为一堆更少的线条！

Answer 4

如何使用单个衬垫正则表达式删除副本和空格。

address = String.Format("{0}, {1}, {2}, {3}, {4}, {5}, {6}",
                        postalAddress.Line1,
                        postalAddress.Line2,
                        postalAddress.Line3,
                        postalAddress.Line4,
                        postalAddress.Suburb,
                        postalAddress.StateCode,
                        postalAddress.Pcode);

address = Regex.Replace(address, @"(,\s)+", @"$1");

具有空值C＃的String.Format

4 个答案: