Question

我有一张桌子，每位销售人员每天销售1条记录

NAME  DATE
joe   1-1-13
joe   1-1-13
joe   1-1-13
dave  1-1-13
joe   1-2-13

我用它来创造＆amp;填充表格

create table #sales (name varchar(10), salesdate date )
insert into #sales (name, salesdate) 
values ('joe', '01-01-2013'), ('joe','01-01-2013'), 
       ('joe', '01-01-2013'), ('dave','01-01-2013'),  
         ('joe','01-02-2013')

我想要一个查询来提高每个销售人员的销售额百分比

（例如，在1-1-13乔当天共有4个单位出售3个单位（75％）但我不知道SQL如何能够提高当天所有销售额的总和，无论销售人员如何

这和我一样接近。

select name, salesdate, count(*) as "dailyTotal"
from #sales
group by name, salesdate

如何包含每日总数，以便它可用于计算当天的总百分比？

Answer 1

不是最优雅的方式，但你可以试试这个 -

select [name],[salesdate], COUNT(*) as dayTotal, 
SUM(COUNT(*)) over() as AllSales, 
(COUNT(*) * 1.0) / SUM(COUNT(*)) over() as dayPercent
FROM [dbo].[sales]
group by [name], [salesdate]

我删除了表名中的＃。顺便说一下，这段代码依赖于OVER（）子句。您可以了解如何自己截断多余的零。

name    salesdate   dayTotal    AllSales    dayPercent
dave    2013-01-01  1           5           0.200000000000
joe   2013-01-01    3           5           0.600000000000
joe   2013-01-02    1           5           0.200000000000

HTH。

如果该查询看起来过于复杂，请先查看此问题。它会让你知道我想要做什么。

select [name],[salesdate], COUNT(*) as dayTotal, 
SUM(COUNT(*)) over() as AllSales
FROM [dbo].[sales]
group by [name], [salesdate]

Answer 2

最受欢迎的答案似乎不正确。

OP有预期答案

例如1-1-13岁的乔当天共有4个单位（75％）出售了3个单位

然而得到的回答显示为60％。

不是对所有数据进行求和，而是应该按天划分，这是一个更好的例子：

select [name],[salesdate], COUNT(*) as dayTotal, 
SUM(COUNT(*)) over(PARTITION BY salesdate) as AllDaySales, 
(COUNT(*) * 1.0) / SUM(COUNT(*)) over(PARTITION BY salesdate) as dayPercent
FROM [dbo].[sales]
group by [name], [salesdate]

Answer 3

使用嵌套查询获取每日总数：

BEGIN

    create table #sales (name varchar(10), salesdate date )

    insert into #sales (name, salesdate) values 
        ('joe', '01-01-2013'), 
        ('joe', '01-01-2013'), 
        ('joe', '01-01-2013'), 
        ('dave', '01-01-2013'),  
        ('joe', '01-02-2013'),
        ('dave', '01-02-2013')

    SELECT name, salesdate, COUNT(*) AS personDailyTotal, MAX(dailyTotal) AS dailyTotal, 
        (COUNT(*) * 100.0) / MAX(dailyTotal) AS [Percent]
    FROM #sales
    INNER JOIN (
        SELECT salesdate as [day], COUNT(*) as dailyTotal 
        FROM #sales 
        GROUP BY salesdate
    ) AS [Total] ON salesdate = [day]
    GROUP BY name, salesdate

END

Answer 4

- 使用以下查询

select T1.salesdate, name ,convert(numeric(18,2),convert(decimal,count(*)) * 100 / T2.total) as percentage from #sales T1
     inner join (
     select salesdate,count(*) as total from #sales group by salesdate
     ) as T2
     on T1.salesdate = T2.salesdate
     group by name,T1.salesdate,T2.total

如何计算分组中的总分百分比？

4 个答案: