我是SSIS的新手，需要一些帮助来确定如何解析这些数据。课程级学习目标需要分成多行，[]中的数据需要移动到它自己的列。任何帮助将不胜感激。 CSV文件包含多个记录。以下示例只是一条记录。
CSV文件的当前格式：
Prefix/Code,Name,Credits,Description,Course-level Learning Objectives
ABE 095,Keys to Academic Success,3.0 ,"Basic .. assessment. ","
Identify learn. [EXPLORE]
Evaluate personal, goals. [ACT]
Utilize development. [EXPLORE]
"
格式化文件需要
Prefix/Code,Name,Credits,Description,Course-level Learning Objectives,Type
ABE 095,Keys to Academic Success,3.0 ,"Basic .. assessment.","Identify learn.", [EXPLORE]
ABE 095,Keys to Academic Success,3.0 ,"Basic .. assessment.","Evaluate goals.", [ACT]
ABE 095,Keys to Academic Success,3.0 ,"Basic .. assessment.","Utilize dev.", [EXPLORE]
答案 0 :(得分：0)
在SSIS 2008中没有直接的方式来使用该文件，但可以在SSIS 2012中完成，然后转动数据，如果你想在SSIS 2008中这样做你应该使用脚本任务来格式化文件然后在DF中使用平面文件源，在脚本任务中你应该使用文件阅读器来实现它，有关拆分此文件的更多信息，请参阅此链接http://sqlbisam.blogspot.com/2013/12/parsing-data-from-one-row-into-multiple.html
答案 1 :(得分：0)
基本步骤：
以下是“第N个”索引函数的代码段：
CREATE FUNCTION [dbo].[udf_NthIndex]
(@Input VARCHAR(8000),
@Delimiter CHAR(1),
@Ordinal INT)
RETURNS INT
AS
BEGIN
DECLARE @Pointer INT,
@Last INT,
@Count INT
SET @Pointer = 1
SET @Last = 0
SET @Count = 1
WHILE (2 > 1)
BEGIN
SET @Pointer = CHARINDEX(@Delimiter,@Input,@Pointer)
IF @Pointer = 0
BREAK
IF @Count = @Ordinal
BEGIN
SET @Last = @Pointer
BREAK
END
SET @Count = @Count + 1
SET @Pointer = @Pointer + 1
END
RETURN @Last
END
GO
;
此方法使用Common Table Expressions，“第N”索引函数和UNPIVOT
解决此问题WITH s1
AS ( SELECT 'ABE 095' AS [Prefix/Code]
, 'Keys to Academic Success' AS Name
, '3.0' AS Credits
, 'Basic .. assessment. ' AS Description
, '
Identify learn. [EXPLORE]
Evaluate personal, goals. [ACT]
Utilize development. [EXPLORE]
' AS [Course-level Learning Objectives]
) , s2
AS ( SELECT [Prefix/Code]
, Name
, Credits
, Description
, dbo.udf_NthIndex( [Course-level Learning Objectives] , CHAR( 13
) , 2
) + 2 AS Type1Start
, dbo.udf_NthIndex( [Course-level Learning Objectives] , CHAR( 13
) , 3
) - dbo.udf_NthIndex( [Course-level Learning Objectives] , CHAR( 13
) , 2
) + 0 AS Type1Length
, dbo.udf_NthIndex( [Course-level Learning Objectives] , CHAR( 13
) , 3
) + 2 AS Type2Start
, dbo.udf_NthIndex( [Course-level Learning Objectives] , CHAR( 13
) , 4
) - dbo.udf_NthIndex( [Course-level Learning Objectives] , CHAR( 13
) , 3
) + 0 AS Type2Length
, dbo.udf_NthIndex( [Course-level Learning Objectives] , CHAR( 13
) , 4
) + 2 AS Type3Start
, dbo.udf_NthIndex( [Course-level Learning Objectives] , CHAR( 13
) , 5
) - dbo.udf_NthIndex( [Course-level Learning Objectives] , CHAR( 13
) , 4
) + 0 AS Type3Length
FROM s1
) , s3
AS ( SELECT s2.[Prefix/Code]
, s2.Name
, s2.Credits
, s2.Description
, RTRIM( LTRIM( SUBSTRING( s1.[Course-level Learning Objectives] , s2.Type1Start , Type1Length
)
)
)AS Type1_chunk
, RTRIM( LTRIM( SUBSTRING( s1.[Course-level Learning Objectives] , s2.Type2Start , Type2Length
)
)
)AS Type2_chunk
, RTRIM( LTRIM( SUBSTRING( s1.[Course-level Learning Objectives] , s2.Type3Start , Type3Length
)
)
)AS Type3_chunk
FROM s1 , s2
) , unpivot1
AS ( SELECT [Prefix/Code]
, Name
, Credits
, Description
, Type_chunk
FROM(
SELECT [Prefix/Code]
, Name
, Credits
, Description
, Type1_chunk
, Type2_chunk
, Type3_chunk
FROM s3
)p UNPIVOT( Type_chunk FOR Type_descrip IN( Type1_chunk
, Type2_chunk
, Type3_chunk
)
)AS unpvt
)
SELECT [Prefix/Code]
, Name
, Credits
, Description
--, Type_chunk
, LEFT( u.Type_chunk , -2 + dbo.udf_NthIndex( u.Type_chunk , '[' , 1
)
)AS [Learning Objectives]
, RIGHT( u.Type_chunk , 1 + LEN( u.Type_chunk
) - dbo.udf_NthIndex( u.Type_chunk , '[' , 1
)
)AS Type
FROM unpivot1 u;
如果您能够使用正则表达式，则可以保存一些代码。在SQL Server 2008中使用RegEx需要CLR。 This book可以很好地向您展示如何逐步完成该操作。该解决方案足以满足每门课程少量的“类型”值。