Question

我有以下内容：

[('first_name', u'Renier'), ('second_name', u''), ('surname', u'de Bruyn'), ('own_transport', u'True'), ('id_number', u'910920254081'), ('id_type', u'IDNumber'), ('id_nationality', u'ZA'), ('disabilities_list', u'Intellectual Disability'), ('disabilities_list', u'Memory Loss'), ('disabilities_list', u'Mental Illness'), ('disabilities_list', u'Physical Disability'), ('disabilities_list', u'Speech and Language Disorders'),...]

如何获取这些元组的值并使用值disabilities_list来创建新列表？

我试过了：

 for k in arr:
        if k == "disabilities_list":
            print k # this only returns "disabilities_list" 5 times

更新

arr是从表单返回的内容，这是我print arr时得到的：

NestedMultiDict([('first_name', u'Renier'), ('second_name', u''), ('surname', u'de Bruyn'), ('race', u'Caucation'), ('own_transport', u'True'), ('id_number', u'9109205021082'), ('id_type', u'IDNumber'), ('id_nationality', u'ZA'), ('disabitity', u'True'), ('disabilities_list[]', u'Memory Loss'), ('disabilities_list[]', u'Mental Illness'), ('disabilities_list[]', u'Physical Disability'), ('disabilities_list[]', u'Speech and Language Disorders'), ('disabilities_list[]', u'Vision Loss and Blindness'), ('mobile_number', u'0828245092'), ('home_number', u'0317016554'), ('email', u'renierdbruyn@hotmail.com'), ('other_contact', u''), ('line1', u'2 Hamilton Road'), ('line2', u''), ('line3', u''), ('city_town', u'Durban'), ('province', u'GP'), ('postal_code', u'3610'), ('suburb', u'Ashley'), ('country', u'ZA'), ('notice_period', u'4 weeks'), ('for_position', u'Developer'), ('curr_renumeration', u'12.0'), ('expect_renumeration', u'123.0'), ('relocate', u'True')])

Answer 1

使用list comprehantion：

>>>arr = [('first_name', u'Renier'), ('second_name', u''), ('surname', u'de Bruyn'), ('own_transport', u'True'), ('id_number', u'910920254081'), ('id_type', u'IDNumber'), ('id_nationality', u'ZA'), ('disabilities_list', u'Intellectual Disability'), ('disabilities_list', u'Memory Loss'), ('disabilities_list', u'Mental Illness'), ('disabilities_list', u'Physical Disability'), ('disabilities_list', u'Speech and Language Disorders'),...]
>>>
>>>[k[1] for k in arr if k[0] == "disabilities_list[]"] 
[u'Intellectual Disability', u'Memory Loss', ...]

修改：根据更新后的问题更新：

>>>[item[1] for item in arr.items() if item[0] == "disabilities_list"]  #  will do, what you want

Answer 2

if k[0] == "disabilities_list":

Answer 3

也许这就是你想要的：

>>> for k,v in arr.iteritems():
...     if k == 'disabilities_list':
...         print v

如何从元组列表中获取值并创建一个新列表

3 个答案: