Question

我有一个表格，其中我有行动和消息作为列我想要计算特定日期时间的特定操作我能够对每个操作求和但不依赖于特定操作。

SELECT DATE(datetime),carpark_name,
Sum(CASE action when '2' then 1 else 0 end) as AcceptedIMG,
Sum(CASE action when '3' then 1 else 0 end) as RejectedIMG, 
Sum(CASE action when '4' then 1 else 0 end) as ChangeIMG,  
sum(CASE action when '23' then 1 else 0 end) as AcceptedViolation,
sum(CASE action when '24' then 1 else 0 end) as RejectedViolation,
sum(CASE action when '25' then 1 else 0 end) as SkippedViolation,
FROM customer_1.audit_trail inner join customer_1.carparks on
customer_1.audit_trail.location_id =  customer_1.carparks.id
 where DATE(datetime)> '2013-12-01'and DATE(datetime)< '2013-12-03'  and location_id = '146'

但这就是我需要添加计数（AcceptedIMG，RejectedIMG，ChangeIMG）或（计数（动作（2,3,4）作为评论。我无法做到这一点。

Answer 1

要获得操作2,3和4的SUM，作为REVIEW列和23,24,25作为CONTRAVENTIO，你可以这样做：

SELECT DATE(datetime),
       carpark_name,
       Sum(CASE action when '2' then 1 else 0 end) as AcceptedIMG,
       Sum(CASE action when '3' then 1 else 0 end) as RejectedIMG, 
       Sum(CASE action when '4' then 1 else 0 end) as ChangeIMG,  
       SUM(CASE WHEN action IN ('2','3','4') then 1 else 0 end) as REVIEW
       sum(CASE action when '23' then 1 else 0 end) as AcceptedViolation,
       sum(CASE action when '24' then 1 else 0 end) as RejectedViolation,
       sum(CASE action when '25' then 1 else 0 end) as SkippedViolation,
       SUM(CASE WHEN action IN ('23','24','25') then 1 else 0 end) as CONTRAVENTION
FROM customer_1.audit_trail 
INNER join customer_1.carparks 
   ON customer_1.audit_trail.location_id =  customer_1.carparks.id
WHERE DATE(datetime) > '2013-12-01'
  AND DATE(datetime) < '2013-12-03'  
  AND location_id = '146'
GROUP BY DATE(datetime),carpark_name

我刚刚将两列添加到您的查询中。如果您不需要个别的，可以将其删除。

使用sum，指望mysql中的同一列

1 个答案: