Question

您好我已经完成了这个随机骰子游戏，需要帮助创建一个循环，让我在用户输入无效数字时，我希望他们再试一次。这是我的代码，请帮助！

import random
dice = int(input("What sided dice do you want to use? (e.g. 4, 6 or 12): "))
if dice == 4:
                random_number = int(random.randrange(1,4))
                print ("You selected a 4 sided dice")
                print ("Your dice has rolled ")
                print (random_number)
elif dice == 6:
                random_number2 = int(random.randrange(1,6))
                print ("You selected a 6 sided dice")
                print("Your dice has rolled ")
                print (random_number2)
elif dice == 12:
                random_number3 = int(random.randrange(1,12))
                print ("You selected a 12 sided dice")
                print("Your dice has rolled  ")
                print (random_number3)
else:
                print(("You didn't select a valid sided dice, try again!"))*

Answer 1

你需要两件事：

一个while循环，一直到你想要的东西为止;和
要检查的可接受答案的集合。

例如，一个简单的解决方案是用当前的input语句包装：

dice = 0
while dice not in (4, 6, 12):
    dice = ...
# continue

Answer 2

使用while循环：

import random
dice = None
while dice not in (4, 6, 12):
    dice = int(input("What sided dice do you want to use? (e.g. 4, 6 or 12): ")
if dice == 4:
            random_number = int(random.randrange(1,4))
            print ("You selected a 4 sided dice")
            print ("Your dice has rolled ")
            print (random_number)
elif dice == 6:
            random_number2 = int(random.randrange(1,6))
            print ("You selected a 6 sided dice")
            print("Your dice has rolled ")
            print (random_number2)

elif dice == 12:
            random_number3 = int(random.randrange(1,12))
            print ("You selected a 12 sided dice")
            print("Your dice has rolled  ")
            print (random_number3)

骰子重复需要帮助

2 个答案: