Question

我无法返回执行echo或print_r的json文件。这是我的代码：

<?php

include 'logFolder.php';   

 $email = "48k2r4l6o60nbn2cug9p0luk7c@group.calendar.google.com";
 $url = "http://www.google.com/calendar/feeds/".$email."/public/full";
 //echo $url;
 $xml = file_get_contents($url);

 $feed = simplexml_load_string($xml);
 $i = 0;
 $ns=$feed->getNameSpaces(true);
 $text = '[';

 foreach ($feed->entry as $entry) {
    $when=$entry->children($ns["gd"]);
    $when_atr=$when->when[0]->attributes();
    $start=$when_atr['startTime'];
    $end=$when_atr['endTime'];
$url = $entry->link->attributes();
$url = $url['href'];
    $title=addslashes($entry->title);
if($i > 0){
    $text = $text . ',';
}
   $text = $text . '{"date":"'.$start.'","type":"meeting","title":"'.$title.'","description":" ","url":"'.$url.'"}';


 // $text[$i] = array("date"=>$start, "type"=>"meeting", "title"=>$title, "description"=>" ", "url"=>$url); 
$File = $logFolder . 'ajson' . '.json' ;
$fh = fopen($File, 'a') or die();
fwrite($fh, '{"date":"'.$start.'","type":"meeting","title":"'.$title.'","description":" ","url":"'.$url.'"}');
fclose($fh);


}
$text = $text . ']';    

echo $text; 


?>

我正在阅读谷歌日历中的事件，我想在我的json文件中包含一些信息。我可以将其保存到文件中，您可以在我的代码中看到，因此变量具有正确的内容。但是，每次我想在屏幕上打印它或以回声方式返回时，我都没有打印出来。你知道发生了什么吗？

Answer 1

使用数组和json_encode（）;

include 'logFolder.php';   

$email = "48k2r4l6o60nbn2cug9p0luk7c@group.calendar.google.com";
$url = "http://www.google.com/calendar/feeds/".$email."/public/full";
//echo $url;
$xml = file_get_contents($url);

$feed = simplexml_load_string($xml);
$i = 0;
$ns=$feed->getNameSpaces(true);
$data = array();
foreach ($feed->entry as $entry) {
    $when=$entry->children($ns["gd"]);
    $when_atr=$when->when[0]->attributes();
    $start=$when_atr['startTime'];
    $end=$when_atr['endTime'];
    $url = $entry->link->attributes();
    $url = $url['href'];
    $title=addslashes($entry->title);

    $data[] = array( 'date' => $start, 'type' => 'meeting', 'title' => $title, 'description', 'url' => $url);
}

$json = json_encode($data);
$File = $logFolder . 'ajson' . '.json' ;

$fh = fopen($File, 'a') or die();
fwrite($fh,$json);
fclose($fh);

echo $json;

Answer 2

你应该使用json_encode。

在你的代码中，这就像是将每个条目单独保存为文件并输出总json（如上面的代码所示）...

<?php
    include 'logFolder.php';   
    $email = "48k2r4l6o60nbn2cug9p0luk7c@group.calendar.google.com";
    $url = "http://www.google.com/calendar/feeds/".$email."/public/full";
    $xml = file_get_contents($url);
    $feed = simplexml_load_string($xml);
    $ns=$feed->getNameSpaces(true);

    //init new array
    $jsonArray=array();
    foreach ($feed->entry as $entry) {
        $when=$entry->children($ns["gd"]);
        $when_atr=$when->when[0]->attributes();
        $start=$when_atr['startTime'];
        $end=$when_atr['endTime'];
        $url = $entry->link->attributes();
        $url = $url['href'];
        $title=addslashes($entry->title);
        //create local json array
        $thisJson=array(
            'date'=>$start,
            'type'=>'meeting',
            'title'=>$title,
            'description'=> ' ' ,
            'url' => $url
        );
        //add local json array to big json array
        $jsonArray[]=$thisJson
        $File = $logFolder . 'ajson' . '.json' ;
        $fh = fopen($File, 'a') or die();
        //save json this json array as text
        fwrite($fh, json_encode($thisJson));
        fclose($fh);
    }

    //output compiled json array
    echo(json_encode($jsonArray));
?>

在otice中有一件事是你的fopen每次使用smae文件名，所以它只是一遍又一遍地覆盖自己。不知道你为什么要这样做，但如果你想要一个包含所有json的文件，你需要在循环之后这样做...

<?php
    include 'logFolder.php';   
    $email = "48k2r4l6o60nbn2cug9p0luk7c@group.calendar.google.com";
    $url = "http://www.google.com/calendar/feeds/".$email."/public/full";
    $xml = file_get_contents($url);
    $feed = simplexml_load_string($xml);
    $ns=$feed->getNameSpaces(true);

    //init new array
    $jsonArray=array();
    foreach ($feed->entry as $entry) {
        $when=$entry->children($ns["gd"]);
        $when_atr=$when->when[0]->attributes();
        $start=$when_atr['startTime'];
        $end=$when_atr['endTime'];
        $url = $entry->link->attributes();
        $url = $url['href'];
        $title=addslashes($entry->title);
        //create local json array
        $thisJson=array(
            'date'=>$start,
            'type'=>'meeting',
            'title'=>$title,
            'description'=> ' ' ,
            'url' => $url
        );
        //add local json array to big json array
        $jsonArray[]=$thisJson
    }

    //output compiled json array
    echo(json_encode($jsonArray));

    //save the json
    $File = $logFolder . 'ajson' . '.json' ;
    $fh = fopen($File, 'a') or die();
    //save json this json array as text
    fwrite($fh, json_encode($jsonArray));
    fclose($fh);    
?>

Answer 3

你有一个简单的错误 - $i永远不会增加，所以你在生成的输出中缺少“，”因此它是非法的json语法。

在foreach循环中，添加：

$i++;

循环结束前

。

但我也同意使用json_encode()更好，但更慢

Answer 4

function getStatusCodeMessage($status)
{

    $codes = Array(
        100 => 'Continue',
        101 => 'Switching Protocols',
        200 => 'OK',
        201 => 'Created',
        202 => 'Accepted',
        203 => 'Non-Authoritative Information',
        204 => 'No Content',
        205 => 'Reset Content',
        206 => 'Partial Content',
        300 => 'Multiple Choices',
        301 => 'Moved Permanently',
        302 => 'Found',
        303 => 'See Other',
        304 => 'Not Modified',
        305 => 'Use Proxy',
        306 => '(Unused)',
        307 => 'Temporary Redirect',
        400 => 'Bad Request',
        401 => 'Unauthorized',
        402 => 'Payment Required',
        403 => 'Forbidden',
        404 => 'Not Found',
        405 => 'Method Not Allowed',
        406 => 'Not Acceptable',
        407 => 'Proxy Authentication Required',
        408 => 'Request Timeout',
        409 => 'Conflict',
        410 => 'Gone',
        411 => 'Length Required',
        412 => 'Precondition Failed',
        413 => 'Request Entity Too Large',
        414 => 'Request-URI Too Long',
        415 => 'Unsupported Media Type',
        416 => 'Requested Range Not Satisfiable',
        417 => 'Expectation Failed',
        500 => 'Internal Server Error',
        501 => 'Not Implemented',
        502 => 'Bad Gateway',
        503 => 'Service Unavailable',
        504 => 'Gateway Timeout',
        505 => 'HTTP Version Not Supported'
    );

    return (isset($codes[$status])) ? $codes[$status] : '';
}


function sendResponse($status = 200, $body = '', $content_type = 'text/json')
{
    $status_header = 'HTTP/1.1 ' . $status . ' ' . getStatusCodeMessage($status);
    header($status_header);
    header('Content-type: ' . $content_type);
    echo $body;


}

尝试在返回json时使用这些函数我将在localhost中创建json的可下载文件

无法返回PHP的json文件

4 个答案: