感谢你们多年来给我的所有帮助。这是另一个问题,像往常一样,任何解释,建议或更正都受到欢迎和赞赏!
我正在使用C ++为AVL树进行分配,目前我正在进行插入,但也需要实现删除,所以尽管这篇文章对插入代码很重要,但任何指针都是如此。如何实现删除最简单的方法来理解我的代码会很棒!
好的,所以我有以下功能来帮助我平衡/插入:
int AVL :: returnBalance(Node* nodeme)
{
return (whatisHeight(nodeme->leftbaby) - whatisHeight(nodeme->rightbaby));
}
int AVL :: whatisHeight(Node* localroot)
{
if(localroot == NULL)
{
return 0;
}else
return localroot->getHeight();
}
void AVL :: adjustHeight(Node* localroot)
{
if(localroot != NULL)
{
localroot->height = 1 + max(whatisHeight(localroot->leftbaby), whatisHeight(localroot->rightbaby));
}
}
bool AVL :: contains(Node* nodeme ,int data)
{
if(!nodeme)
{
return false;
}else
if(data == nodeme->value)
{
return true;
}
if(data < nodeme->value)
{
return contains(nodeme->leftbaby,data);
}else
{
return contains(nodeme->rightbaby,data);
}
}
// Rotation
void AVL :: rotateLeft(Node* localroot)
{
Node * temp = localroot->rightbaby;
localroot->rightbaby = temp->leftbaby;
temp->leftbaby = localroot;
localroot = temp;
adjustHeight(localroot);
adjustHeight(localroot->rightbaby);
adjustHeight(temp);
}
void AVL :: rotateRight(Node* localroot)
{
Node * temp = localroot->leftbaby;
localroot->leftbaby = temp->rightbaby;
temp->rightbaby = localroot;
adjustHeight(localroot);
adjustHeight(localroot->leftbaby);
adjustHeight(temp);
localroot = temp;
}
我的插入和插入递归函数编写如下
bool AVL :: add(int data)
{
if(!contains(root, data))
{
insertRecursive(root,data);
return true;
}else
{
return false;
}
}
Node * AVL :: insertRecursive(Node * nodeme, int data)
{
// getting a number ready to print
int num1 = data;
string out1;
ostringstream convert1;
convert1 << num1;
out1 = convert1.str();
cout << "running recursive insert -- value: " << out1 << endl;
if(root == NULL)
{
cout << "adding root node" << endl;
Node * temporary = new Node(data);
temporary->height = 0;
root = temporary;
return root;
}else
if(nodeme == NULL)
{
cout << "adding at local" << endl;
nodeme = new Node(data);
nodeme->height = 0;
return nodeme;
}else
if(data < nodeme->value)
{
nodeme->leftbaby = insertRecursive(nodeme->leftbaby,data);
// balancing and stuff
adjustHeight(nodeme);
if ((returnBalance(nodeme) == -2 )&& (returnBalance(nodeme->leftbaby) == -1))
{
cout << "rotating right" << endl;
rotateRight(nodeme);
}else
if((returnBalance(nodeme) == -2) && (returnBalance(nodeme->leftbaby) == 1))
{
cout << "rotating left ---- 1" << endl;
rotateLeft(nodeme->leftbaby);
cout << "rotating right" << endl;
rotateRight(nodeme);
}else
if((returnBalance(nodeme) == 2) && (returnBalance(nodeme->leftbaby) == 1))
{
cout << "rotating left" << endl;
rotateLeft(nodeme);
}
else
if((returnBalance(nodeme) == 2) && (returnBalance(nodeme->leftbaby) == -1))
{
cout << "rotating right --- 2" << endl;
rotateRight(nodeme->leftbaby);
cout << "rotating left" << endl;
rotateLeft(nodeme);
}
adjustHeight(nodeme);
//
return nodeme;
}
else
{
nodeme->rightbaby = insertRecursive(nodeme->rightbaby,data);
// balancing and stuff
adjustHeight(nodeme);
if ((returnBalance(nodeme) == -2 )&& (returnBalance(nodeme->leftbaby) == -1))
{
cout << "rotating right" << endl;
rotateRight(nodeme);
}else
if((returnBalance(nodeme) == -2) && (returnBalance(nodeme->leftbaby) == 1))
{
cout << "rotating left --- 3" << endl;
rotateLeft(nodeme->leftbaby);
cout << "rotating right" << endl;
rotateRight(nodeme);
}else
if((returnBalance(nodeme) == 2) && (returnBalance(nodeme->leftbaby) == 1))
{
cout << "rotating left" << endl;
rotateLeft(nodeme);
}
else
if((returnBalance(nodeme) == 2) && (returnBalance(nodeme- >leftbaby) == -1))
{
cout << "rotating right --- 4" << endl;
rotateRight(nodeme->leftbaby);
cout << "rotating left" << endl;
rotateLeft(nodeme);
}
cout << "adjust height" << endl;
adjustHeight(nodeme);
//
return nodeme;
}
}
cout s仅用于测试,我的类使用给定的测试驱动程序,因为事实证明我的树在添加0,1,2,3到9时不匹配。它在添加时失败2.注意此树中不允许重复的值,因此包含函数。
现在,在我的脑海里,我正在添加一棵树,更新高度,检查平衡,然后在我继续之前旋转,所以在我的脑海里,我保持树的平衡。显然这没有正确实现,所以我需要一些方向!
预期的树是:
0 1 0 0 1 2
我要回来了
0 0 1 1 11 2
我为此通过如此多的代码道歉,我确信没有多少人真的想要阅读它,但只是看了一眼你可能想要呕吐并提供一个很好的解释。
非常感谢! -MJ
答案 0 :(得分:0)
轮流:
localroot = temp;
您应该通过引用传递参数。如果没有,则无法更改实际参数,您将获得内存泄漏。
AVL :: insertRecursive中的nodeme也是如此。